y=mx+b m is the slope, b is the y-intercept (where the line will cross the y axis.
If y = mx + b, then x = (y-b)/m (for m not equal to zero).
y = mx + bAt the x-intercept, y = 0 :0 = mx + bSubtract b from each side of the equation :-b = mxDivide each side by 'm' :-b/m = x
y=mx+b is the equation for a linear relationship. y= the dependant variable m= the slope of the line x= the independent variable b= the y-intercept
The equation of a line is y=mx+b, when m is the slope of the line and b is the y-intercept.
If you mean the straight line equation of: y = mx+b then m is the slope and b is the y intercept
y=mx+b m is the slope, b is the y-intercept (where the line will cross the y axis.
If you mean: y = mx+b then m is the slope and b is the y intercept
The equation of the line can be written as y = mx + b, where m is the slope and b is the y-intercept. Since the x-intercept is a, the point (a, 0) lies on the line. Substituting these values into the equation, you can find the value of b. The final equation will be y = mx - m*a.
If y = mx + b, then x = (y-b)/m (for m not equal to zero).
Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
y = mx + bAt the x-intercept, y = 0 :0 = mx + bSubtract b from each side of the equation :-b = mxDivide each side by 'm' :-b/m = x
The equation y = mx + b is the equation for a line in slope intercept form, with m being the slope, and b being the y-axis intercept.
y=mx+b is the equation for a linear relationship. y= the dependant variable m= the slope of the line x= the independent variable b= the y-intercept
y = mx + b y - b = mx (y - b) / x = m (m is the slope, except where x = 0)
Y=mx+b is the equation of a straight line graph in mathematics. Answer Y = mX + b This is the general form of an Equation for a Straight Line when plotted on a coordinates of X versus Y. where. m = slope of the line b = intercept point of the Y-Axis (or the value of Y when X=0)
The equation of a line is y=mx+b, when m is the slope of the line and b is the y-intercept.