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This is a Hardy Weindburg situation

P represents the percentage of the population that has a dominant allele... now there can only be two alleles one is dominant and one is recessive... q is the recessive allele

This means that p+q=1 and so q has to be equal to 0.32

If you do the square of p (p^2) then that gives you the number of people who are homozygous dominant

If you do the square of q (q^2) then that gives you the number of people who are homozygous recessive

If you do 2*(p*q) then that will give you the number of people who are heterozygous

Hope this helps...

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13y ago

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