1 hour = 3600 seconds 1760 yards = 1 mile 3 yd/s = 3 yd/s x 3600 s/hr = 10800 yd/hr 10800 yd / hr = (10800 yd ÷ 1760 yd/mi)/hr = 6 3/22 mph ≈ 6.14 mph
If by s and v you mean surface area and volume, then SA=6x^2 and V=x^3 where x is the length of a side.
Let V=volume V^(1/3)=Side Length=S 6*S^2=Surface Area Surface Area=6*(Volume)^(2/3)
Assuming you mean the radius is 8 feet - 1608.50 ft3 (rounded to 2 decimal places)
given the length of a side as S, the volume is: SQRT(2)*S3/12 Where SQRT(2) is the square root of 2 (~1,414) and S3 is the length of a side cubed.
A square's area is side^2. The perimeter is side*4. I'll assume you meant 25 square yards. A=25 yd=s^2 s=5 yd P=5*4 yd=20 yd
1 m = 1.094 yd 100 m * (1.094 yd/m) = 109.4 yd 109.4 yd / 10.6 s = 10.3208 yd/s 100 yd / (10.3208 yd/s) = 9.6892 s
1 hour = 3600 seconds 1760 yards = 1 mile 3 yd/s = 3 yd/s x 3600 s/hr = 10800 yd/hr 10800 yd / hr = (10800 yd ÷ 1760 yd/mi)/hr = 6 3/22 mph ≈ 6.14 mph
If by s and v you mean surface area and volume, then SA=6x^2 and V=x^3 where x is the length of a side.
(48 ft./s)(1 yd./3 ft.)(60 s/min.) = 960 yd./min.
Let V=volume V^(1/3)=Side Length=S 6*S^2=Surface Area Surface Area=6*(Volume)^(2/3)
Suppose the plane faces of the cylinder lie in the planes that are s units above and below the centre of the sphere. Therefore, the height of the cylinder is 2*s units. Also, by Pythagoras's theorem, the radius of the cylinder, x units, is such that x^2 + s^2 = R^2 = 16 Therefore x^2 = 16 - s^2. Volume of cylinder = pi*x^2*2*s = 2*pi*(16-s^2)*s = 2*pi*(16*s - s^3) Then dV/ds = 0 implies that 2*pi*(16 - 3*s^2) = 0 so s^2 = 16/3 and so s = 4/sqrt(3) The second derivative is -2*pi*6*s which is negative and so the volume is a maximum. When s = 4/sqrt(3), Volume of cylinder = 2*pi*[16 - 16/3]*4/sqrt(3) = 2*pi*32/3*4/sqrt(3) = 256*pi/[3*sqrt(3)] = 256*sqrt(3)*pi/9 = 49.2672*pi approx. The volume of the cylinder is approx 0.5774 times that of the sphere.
if "s" is the length of a side, then the surface area A is 6s^2 (6 times s squared) the volume V is s^3 (s cubed) so s = V^(1/3) and A = 6V^(2/3)
Assuming you mean the radius is 8 feet - 1608.50 ft3 (rounded to 2 decimal places)
Cubic displacement inches (the volume in inches displaced by the piston/s).
given the length of a side as S, the volume is: SQRT(2)*S3/12 Where SQRT(2) is the square root of 2 (~1,414) and S3 is the length of a side cubed.
A hollow truncated cone is a geometric shape that is cone-shaped. The formula to calculate the volume is s^2=h^2 + (R-r)^2.