You would be in the 99th percentile (98.61, to be more precise).
(527-500)/100= Z-score. Then, you should look at the table for this given Z score
It is the 31st percentile.
Mean.
From the given information it is not possible. You need to find the score, S, such that the percentage of people scoring S or below is 40%.
Yes, 85th percentile is a passing mark.
You would be in the 99th percentile (98.61, to be more precise).
you scored 85% better than other people taking the same test at the same time
normal body weight
glucocorticoid-responsive element (GRE)
If you wish to determine if you are overweight the following information may help:The following is the typical information that is used to determine if a child is underweight, normal weight, overweight, or obese; you must start with a children's weight chart, in which you simply plan/plot your height, BMI (Body Mass Index) and weight to determine where you fall with others children of your age group.Now to determine if you are underweight, the BMI should be below the 5th percentile; if you are of normal weight, the BMI should be at the 5th percentile but less than the 85th percentile; if your are overweight, the BMI should be the 85th percentile but below the 95th percentile; and finally, if you are of obese weight, the BMI is at or above the 95th percentile.
(527-500)/100= Z-score. Then, you should look at the table for this given Z score
The ideal weight for a child depends on their height and age. A boy or a girl, that's 12 years old, would be considered overweight if they fall in the 85th to 95th percentile and obese if they are above the 95th percentile.
mean: 400std deviation: 25z-score = ( 380 - 400 ) / 25 = -0.8The probability of getting a score lower than this is about 21.1%. Or, in other words, about 78.8% score higher.Please see the link.
Guest Relationship Executive
Yes, the mean (and median and mode) is the 50th percentile of any normal distribution.
It is the minimum value.