answersLogoWhite

0

It is a series of impulses (Dirac Delta functions), each positioned at the point where the square wave changes amplitude. For a negative change in amplitude, the impulse is -inf; likewise, for a positive change in amplitude, the impulse is +inf.

The fourier expansion of the square wave is:

4/pi sum_{k=1}^\infty [ sin((2k-1)*w*t) / (2k-1) ] Likewise, its derivative is:

4/pi*w sum_{k=1}^\infty [ cos((2k-1)*w*t) ]

If you plot, the first 50 terms, you will get a pretty good idea of what it looks like. impulse

User Avatar

Wiki User

17y ago

Still curious? Ask our experts.

Chat with our AI personalities

CoachCoach
Success isn't just about winning—it's about vision, patience, and playing the long game.
Chat with Coach
FranFran
I've made my fair share of mistakes, and if I can help you avoid a few, I'd sure like to try.
Chat with Fran
JordanJordan
Looking for a career mentor? I've seen my fair share of shake-ups.
Chat with Jordan

Add your answer:

Earn +20 pts
Q: What does the derivative of a square wave look like?
Write your answer...
Submit
Still have questions?
magnify glass
imp