answersLogoWhite

0

It is a series of impulses (Dirac Delta functions), each positioned at the point where the square wave changes amplitude. For a negative change in amplitude, the impulse is -inf; likewise, for a positive change in amplitude, the impulse is +inf.

The fourier expansion of the square wave is:

4/pi sum_{k=1}^\infty [ sin((2k-1)*w*t) / (2k-1) ] Likewise, its derivative is:

4/pi*w sum_{k=1}^\infty [ cos((2k-1)*w*t) ]

If you plot, the first 50 terms, you will get a pretty good idea of what it looks like. impulse

User Avatar

Wiki User

17y ago

Still curious? Ask our experts.

Chat with our AI personalities

RossRoss
Every question is just a happy little opportunity.
Chat with Ross
JordanJordan
Looking for a career mentor? I've seen my fair share of shake-ups.
Chat with Jordan
JudyJudy
Simplicity is my specialty.
Chat with Judy

Add your answer:

Earn +20 pts
Q: What does the derivative of a square wave look like?
Write your answer...
Submit
Still have questions?
magnify glass
imp