a = 1; b = 2; c = 3 111 + 222 = 333
what is the greets possible 9 digit number that uses each of the digits 1-3 times
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
100000 2847239582
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
a = 1; b = 2; c = 3 111 + 222 = 333
Choose from 4 for the first number, 3 for the second number, and 2 for the third number. Therefore there are 4*3*2 = 24 three digit numbers can be formed from 3769 if each digit is used only once.
what is the greets possible 9 digit number that uses each of the digits 1-3 times
It is its positional place value within a number
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
100000 2847239582
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
A smaller 3 digit number or a 2 digit number (99).
They are: 600, 30 and 3
3 100 423 080.
When creating a 3-digit number using the digits 3, 6, and 9, with repetition allowed, each digit has 3 possible choices. Therefore, the total number of 3-digit numbers that can be formed is calculated by multiplying the number of choices for each digit, which is 3x3x3 = 27. So, there are 27 different 3-digit numbers that can be made using the digits 3, 6, and 9 with repetition allowed.
9999 is the 4-digit number and 999 is the 3-digit number.