Smaller
The top point
false
I assume you mean the curve of length against applied force (or mass) for a wire. The beginning part of the curve should be a straight line, and this is where the deformation is elastic. When the substance passes its elastic limit, the line starts to curve up.
You don't. An equation with two variables can be graphed as a line or a curve on x-y coordinates. When you do that, EVERY point on the line or curve satisfies the equation. You can't 'solve' it ... i.e. come up with unique values for 'x' and 'y' ... until you have another equation. It represents another line or curve on the graph, and the 'solution' represents the point (or points) where the graphs of the two equations intersect.
The peak's area under the curve represents the percentage of light energy absorbed. To calculate the percentage, divide the peak's area by the total area under the curve and multiply by 100.
The "bell curve" of anything, with the peak of the curve supposedly at a score of 100.
A bell curve is a graph that depicts a large rounded peak tapering away at each end of normal distribution. A bell curve is a mathematical concept with the curve concentrated in the center.
Use those speacial reading graphs You should have a hydrograph to look at. Look at the curve on this graph, the highest point on this curve is the peak flow. It cannot be calculated, just read off a graph. Peak Flow = Tidal Volume x 60 / I-time
No, a calibration curve based on peak height alone may not give accurate results for the determination of caffeine. Peak area is a more reliable measure for quantification as it takes into account both peak height and width, which can be influenced by various factors in the experiment such as sample matrix effects and instrument settings. Using peak area for the calibration curve would improve the accuracy and reliability of the results.
when we look at the curve ,, we can see that before the peak point curve has greater slope as compared to the slope after the peak point .. the reason is PL is given as I^2RL ,,, current is a squared term here . before peak point current is greater so overall change in power is much greater but after peak point RL is greater and current is less now the load resistance is not a squared term... so slope will be less. therefore the curve is not symetrical
That is about where the peak of its blackbody radiation curve is, as determined by the photosphere temperature.
Curve that represents the curve between cost vs time or resources vs time in primavera planning software... Since it looks like "s" its called s-curve...
Smaller
The difference between curve A and curve B on an energy diagram is most likely due to the activation energy required for the reaction. Curve A likely represents a reaction with a higher activation energy, resulting in a slower reaction rate compared to curve B, which represents a reaction with a lower activation energy and a faster reaction rate.
In science, the height of a peak or a trough is the maximum distance from the peak to the baseline or from the trough to the baseline. It represents the amplitude of the wave or signal at that point.
The slope of the curve.