It is an irrational number that lies between 7 and 8
Only two prime numbers lie between 50 and 60. They are 53 and 59.
Let's call this number b 42000 = 24 x 3 x 53 x 7 We have 42000 x b = a2 and a is an integer Then a = sqrt(42000 x b) = sqrt(b) x sqrt(24 x 3 x 53 x 7) sqrt(24 x 3 x 53 x 7) = 22 x sqrt(3) x 5 x sqrt(5) x sqrt(7) For a to be an integer sqrt(b) must be sqrt(3) x sqrt(5) x sqrt(7) at least Thus b = 105
Counting only integer square roots, since sqrt(5) is equal to ±25 and sqrt(6) is equal to ±36, the square roots of the integers between 25 and 36, and between -36 and -25, are between 5 and 6 inclusive.
The mean proportion between two numbers, ( a ) and ( b ), is calculated using the formula ( \sqrt{a \times b} ). For 5 and 15, this would be ( \sqrt{5 \times 15} = \sqrt{75} ). Simplifying ( \sqrt{75} ), we get ( 5\sqrt{3} ), which is approximately 8.66. Thus, the mean proportion between 5 and 15 is ( 5\sqrt{3} ).
-sqrt(59) < -3, 6 < sqrt(59)
There are many. One example is -sqrt(175) < -3 < -2 < +sqrt(175)
0 and 1 are consecutive whole numbers that lie between -sqrt(124) and +sqrt(124).
sqrt(13) = 3.6... so it lies between 3 and 4.
Only two prime numbers lie between 50 and 60. They are 53 and 59.
The square root of 75 lies between 8 and 9.
20*pi is significantly larger than 4*sqrt(53).
Counting only integer square roots, since sqrt(5) is equal to ±25 and sqrt(6) is equal to ±36, the square roots of the integers between 25 and 36, and between -36 and -25, are between 5 and 6 inclusive.
Let's call this number b 42000 = 24 x 3 x 53 x 7 We have 42000 x b = a2 and a is an integer Then a = sqrt(42000 x b) = sqrt(b) x sqrt(24 x 3 x 53 x 7) sqrt(24 x 3 x 53 x 7) = 22 x sqrt(3) x 5 x sqrt(5) x sqrt(7) For a to be an integer sqrt(b) must be sqrt(3) x sqrt(5) x sqrt(7) at least Thus b = 105
121 < 128.3 < 144So -12 < negative sqrt(128.3) < -11and11 < sqrt(128.3) < 12121 < 128.3 < 144So -12 < negative sqrt(128.3) < -11and11 < sqrt(128.3) < 12121 < 128.3 < 144So -12 < negative sqrt(128.3) < -11and11 < sqrt(128.3) < 12121 < 128.3 < 144So -12 < negative sqrt(128.3) < -11and11 < sqrt(128.3) < 12
53 and 55
251.5 = 253/2 = [ sqrt(25) ]3 = 53 = 125
The mean proportion between two numbers, ( a ) and ( b ), is calculated using the formula ( \sqrt{a \times b} ). For 5 and 15, this would be ( \sqrt{5 \times 15} = \sqrt{75} ). Simplifying ( \sqrt{75} ), we get ( 5\sqrt{3} ), which is approximately 8.66. Thus, the mean proportion between 5 and 15 is ( 5\sqrt{3} ).