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3 4 6 9 13 sequence?
recursive rule: term(n+1) = term(n) + (n) also, n starts at 0 and term(1)=3 term(1) = 3 ; (n=0) term(2) = term(1) + (1) = 4 term(3) = term(2) + (2) = 6 term(4) = term(3) + (3) = 9 term(5) = term(4) + (4) = 13 . . .
What is the nth term to the fibornacci sequence?
the (n-1)th term plus the (n-2)th term.
How do you work out the third term of 10 subtract n squared?
To solve the third term of 10-n², substitute the number 3 for n. 10-n² =10-3² =10-9 =1 The third term of 10-n² is 1.
What is the 50th term for 100-n?
50th term means n = 50 So the term is 100-50 = 50
What is the rule in these nunbers 3-7 4-10 5-13?
Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc... Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1). For even terms in the sequence, n(i)= (n (i - 2)th term -3).
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