Fist you've got to find the volume of the sphere, if the radius was 4cm then it would be...4/3*pi*r3=268cm
V of cylinder= pi*r2*l (the radius for example is 8cm)
268=pi*64*l
L=268/64pi =1.3cm
The level of the liquid in the cylinder rose by 10 mL when the rock was submerged in the liquid.
First obtain the height of the cylinder. Height = 1077/area of the base (i.e H = 1077 divided by pie-radius-squared) Next get how much water does 1cm of height contain. Take 1077/height. Therefore, volume of rock = 1cm height's volume x 3
Note the level of water in the graduated cylinder. Place the rock into the water carefully. Note the higher level to which the water rises. The difference between the old level and the new level is the volume displaced by the rock.
It is quite simple if it is a regular shaped object like a cylinder or a cube. For example if you wanted calculate the volume of a cylinder you need to know the radius of the circular cross-section of the cylinder - this is the measurement from the centre of the circle, to the outer-edge and then multiply that by the height of the cylinder. For irregular shaped objects don't think there is a simple mathematical way if you don't know the density but you can always use water displacement to get a volume measurement. Just drop the object you want to know the volume off into a graduated cylinder partially filled with water - the amount the level rises will be roughly equal to the volume of the object you dropped in.
Put water in the cylinder to a level that would cover the object. Drop the item in and if it sinks, read the new level on the graduations. The difference in volume between the two marks, is the volume of the item.
0.6 cm
The displaced liquid volume is equal to the volume of the cylinder. The volume of the cylinder is πr^2h, so in this case it is π(2cm)^2(4cm) = 16π cm^3. The volume displaced is equal to the rise in the liquid level in the graduated cylinder. Using the formula for the volume of the liquid in a cylinder (πr^2h), we can solve for the height (h). The rise in the liquid level will be approximately 1.06 cm.
To calculate the rise in the water level when a spherical ball is immersed in water in a vertical cylinder, you can use the Archimedes' principle, which states that the buoyant force on an object immersed in a fluid is equal to the weight of the fluid displaced by the object. The volume of water displaced by the ball is equal to the volume of the ball. Calculate the volume of the ball using the formula for the volume of a sphere, then use this volume to determine the rise in water level.
The level of the liquid in the cylinder rose by 10 mL when the rock was submerged in the liquid.
46m2
Surface tension is in equilibrium. The shape of a sphere has the highest volume to surface area to radius ratio. This shape is the lowest energy level a volume of liquid can have. Deforming it into another shape would involve an increase in surface area and an increase in the average radius.
When you put an object in a graduated cylinder, the water level rises because the object displaces water equal to its volume. This is known as Archimedes' principle. The increase in water level corresponds to the volume of the object that is submerged in the water.
To measure a rock using a measuring cylinder, you can follow these steps: Fill the measuring cylinder with water up to a marked level. Note down the initial water level. Carefully place the rock into the water, ensuring it is fully submerged. Measure the new water level and calculate the difference to determine the volume of the rock.
The energy level that looks like a sphere is the lowest level.
Lucario learns Aura Sphere at level 37.
Mewtwo learns Aura Sphere at level 93.
Lucario learns Aura Sphere at level 51.