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2x2 + 2x - 12 = 0; first factor out 2

2(x2 + x - 6) = 0; since -6 = 3(-2) and 3 + (-2) = 1 factor the trinomial such as

2(x + 3)(x - 2) = 0; let each factor equal to zero

x + 3 = 0; subtract 3 to both sides

x = -3

or

x - 2 = 0 ad 2 to both sides

x = 2

Thus, the solution set is {-3, 2}.

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