15x+12y+22+3w-2y+3x+14-12+3w original = 15x+3x+12y-2y+3w+3w+22+14-12 group = 18x+10y+6w+24 answer
Expressed as an algebraic equation, this would equal 3w.
The roots (or solutions) are the numbers that 'w' must be in order to make the equation true.Since the highest power of 'w' in the equation is the first power, there's only one solution.3w - 14 - 6 = 21Combine the -14 and the -6 on the left side:3w - 20 = 21Add 20 to each side:3w = 41Divide each side by 3 :w = 41/3 = 132/3
7w + 2 = 3w + 94 Subtract 3w from both sides: 4w + 2 = 94 Subtract 2 from both sides: 4w = 92 Divide both sides by 4: w = 23
3w + 12
7+3w-13x
If: 3w = 42 Then: w = 14
Without an equality sign the given expression can't be considered to be an equation
3w + 4e + 7w - e3 = 10w - e
This is an example of the "commutative" property.
no
You can't solve it - you only have one equation and two unknowns. You need 2 equations to solve this.