12X = 1
divide both sides integers by 12
X = 1/12
check
12(1/12) = 1
1 = 1
checks
X=.75
x works out as 5/3
x2+12x+11=0 (x+11)(x+1)=0 x=-11 or x=-1
-1
3x+12x = 15 15x = 15 x = 1
12x = x + 3 11x = 3 x = 3/11
x2+12x-13=0 The factor of x2+12x-13 is: (x+13)(x-1) So: x+13 = 0 or x-1 = 0 The answer is: x=-13 or x=1
(12x -4) = 0 12x = 4 x = 1/3
Y=4, X=1
Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12
12x = 4(x+5) 3x = x+5 divide by 4 2x = 5 subtract x x = 2.5 divide by 2
2x2 + 6 = 30 is your statement.2x2 = 24x2 = 12x = ±√12x = ±√(4*3)x = 2√3 or x = -2√3