5x + 3x2 - 2x is not an equation, so there is no value of x to be determined. If you want to simplify it, you would get:
5x + 3x2 - 2x
= 3x + 3x2
You could also factor that out, and get 3x(1 + x)
If you want to treat it as a function and find it's range with respect to x, we can see that it describes a parabola. To find it's apex, we can take it's derivative and solve for x = 0:
f(x) = 3x2 + 3x
f'(x) = 6x + 3
0 = 6x + 3
0 = 2x + 1
2x = 1
x = 1/2
Now we can find the corresponding y-coordinate at that x location:
f(1/2) = 3(1/2)2 + 3(1/2)
f(1/2) = 3/4 + 3/2
f(1/2) = 3/4 + 6/4
f(1/2) = 9/4
So the apex of the parabola described by that function occurs at the point (1/2, 9/4). By taking the second derivative (f''(x) = 6), we can see that the rate of change of the slope of the tangent is positive, which means that this is a parabola that moves upwards from it's apex. That tells us that for any real value of x, f(x) will always be greater than or equal to 9/4.
No. 3x plus 2x = 5x. 3x multiplied by 2x = 6x²
3x^2 + x + 2x^2 = 5x^2 + x
5x-72
2x + 3x = 5x
Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7
No. 3x plus 2x = 5x. 3x multiplied by 2x = 6x²
2x + 20 = 3x20 = 3X - 2X20 = X
3x^2 + x + 2x^2 = 5x^2 + x
5x-72
-8x
2x + 3x = 25 → x ≈ 2.663844636
3x + 2x - 8x + 2x = -x
2x minus 3x is equal to -x.
2x + 3x = 5x.
2x + 3x = 5x
Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7
2x+3x = 5x