Y = 7 + 2X - 2X^2
set = to 0
7 + 2X - 2X^2 = 0
arrange in standard quadratic form
2X^2 - 2X - 7 = 0
I am too lazy to factor, so the quadratic equation........
-b +/- sqrt(b^2-4ac)/2a
a = 2
b = -2
c = -7
check with discriminant. b^2 - 4ac
-2^2 - 4(2)(-7) = 60; greater than 1; 2 real roots
-(-2) +/- sqrt[(-2)^2 - 4(2)(-7)]/2(2a)
2 +/- sqrt(60)/4
2 +/- 2sqrt(15)/4
not pretty, just, save factoring, exact
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2x + 52 = 7 2x + 25 = 7 2x = 7 - 25 2x = -18 x = -18/2 x = -9
If x=4 then 2x+7 =
X=7
I suggest you use the quadratic formula, with a = 3, b = -2, c = 7.
-7 +2x = x + 8 2x - x = 7 + 8 x = 15