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2Rb(s) + 2H2O(l) --> 2RbOH(aq) + H2(g)
FOR WIRE A , RA = rho L/A = rho L/pie* r square -equation 1 RB = rho 2L/pie(2r)square = rho 2L/4 pie*r square =rho L/2 pie * r square -equation 2 RA/RB = rho L/pie * r square * 2 pie *r square/rho L RA/RB = 2 RA = 2RB , RB = RA/2 1/Rp = 1/RA + 1/RB =1/RA +1/RB 1/Rp = 3/RA Rp/RA = 1/3 Hence the ratio is 1:3
Are you asking to have that equation solved for 'a' ?r = ab / (a + b)Multiply each side by (a + b) . . . ra + rb = abSubtract 'ra' from each side. . . . rb = ab - raFactor the right side . . . . . . . . . rb = a (b - r)Divide each side by (b - r) . . . . . a = rb / (b - r)
Rubidium
It might be China Post Registered Mail.
K+
Rb (rubidium) is the largest element among K (potassium), Rb (rubidium), Na (sodium), and Li (lithium). This is because as you move down a group in the periodic table, the atomic size increases due to the addition of more electron shells.
Rb
The species with the smallest atomic radius among K, Mg, Rb, and Ca is Rb (Rubidium). This is because atomic radius tends to decrease across a period from left to right in the periodic table, and Rb is located towards the right side of this group of elements.
Rb+ has a smaller radius than K+ due to increased effective nuclear charge in rubidium. Therefore, K+ has a smaller radius than Rb.
The element Rb (Rubidium) is in period 5 of the periodic table.
The atomic radius of Sr (Strontium) is larger than that of Rb (Rubidium). This is because atomic radius generally increases down a group in the periodic table, and Sr is located below Rb in the same group.
Smallest to largest is going down the group 1. I.e. Li is smallest<Rb<Cs
The element RB, which is rubidium, has 37 protons.
The element with the smallest first ionization energy is Francium, as it is located in Group 1 of the periodic table and has the largest atomic size. Among the elements listed, lithium (Li) would have the smallest first ionization energy as it is closer to the upper right of the periodic table compared to sodium (Na), potassium (K), and rubidium (Rb).
The atomic radius of rubidium (Rb) is approximately 248 picometers. This is the distance from the nucleus to the outermost electron shell in a rubidium atom.
Rubidium.