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What else would need to be congruent to show that abc is congruent to def by the aas theorem?
To show that triangles ABC and DEF are congruent by the AAS (Angle-Angle-Side) theorem, you need to establish that two angles and the non-included side of one triangle are congruent to the corresponding two angles and the non-included side of the other triangle. If you have already shown two angles congruent, you would need to prove that one of the sides opposite one of those angles in triangle ABC is congruent to the corresponding side in triangle DEF. This additional information will complete the criteria for applying the AAS theorem.
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What else would need to be congruent to show that ABCis congruent toXYZ by SAS?
The answer depends on what is already known about the two triangles.
What else would be need to be congruent to show that triangle JKL congruent MNO by AAS?
To show that triangle JKL is congruent to triangle MNO by the Angle-Angle-Side (AAS) theorem, you need to establish that two angles and the non-included side of triangle JKL are congruent to two angles and the corresponding non-included side of triangle MNO. Specifically, you would need to verify that one of the angles in triangle JKL is congruent to one of the angles in triangle MNO, and that the side opposite the angle in triangle JKL is congruent to the corresponding side in triangle MNO. This would complete the necessary conditions for AAS congruence.
What else would need to be congruent to show that abc is congruent to def by ASA?
"What else" implies there is already something that is congruent. But since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer. no correct
What additional information will allow you to prove the triangles congruent bu HL theorem?
To prove two triangles congruent by the Hypotenuse-Leg (HL) theorem, you need to know that both triangles are right triangles. Additionally, you must establish that the lengths of their hypotenuses are equal and that one pair of corresponding legs is also equal in length. With this information, you can confidently apply the HL theorem to conclude that the triangles are congruent.
What is a hypotenuse theorem?
If the hypotenuse of a right triangle is congruent to the corresponding part of another right triangle, then the triangles are congruent. ========================================== Another contributor, in shock, stopped by to point out: That may (or may not) be a "hypotenuse theorem", but you really need to be careful trying to use it, because it's not true!
What else would need to be congruent to show that abc def by the aas theorem?
AC is congruent to DF.
What else would need to be congruent to show that abc congruent xyz by SAS?
__ - __ AC = XZ = is the similar sign
What else would need to be congruent to show that abc def by asa?
Angle "A" is congruent to Angle "D"
What else would need to be congruent to show that ABCis congruent toXYZ by SAS?
The answer depends on what is already known about the two triangles.
What else would need to congruent to show that abc equals pqr by sss?
That depends on which sides have not been proven congruent yet.
What else would need to be congruent to show that efg jkl by sss?
For a start, you would need to know what efg and jkl are.
What else would need to be congruent to show abc is congruent to def by AAS?
"What else" implies there is already something that is congruent. But since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
What else would need to be congruent to show that abc pqr by sss?
Bc= qr
What else would need to be congruent to show that stu jkl by sas?
Su jL
What else would need to be congruent to show that efg pqr by asa?
bc yz
What else would need to be congruent to show that triangle abc is congruent to xyz by SAS?
"What else" implies there is already something that is congruent. But since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
What else would need to be congruent to show that abc xyz by sas?
Line segment BC is congruent to Line Segment YZ
