Only one and eleven. Eleven is a Prime number. Prime numbers are divisible by one and themselves only.
220
15 and -4
The two numbers that multiply to 24 and add up to -11 are -3 and -8. When multiplied, -3 × -8 equals 24, and when added, -3 + -8 equals -11.
The two numbers that add to -11 and multiply to 19 are -10 and -1. When you add them together, -10 + (-1) equals -11. When you multiply them, -10 × -1 equals 10, not 19. Therefore, there are no two real numbers that satisfy both conditions simultaneously.
The numbers that multiply to give you 121 and add to give you 8 are 11 and -11. When multiplied, 11 × -11 equals 121; however, they do not add up to 8. The correct numbers that meet both conditions are 11 and -3, as 11 × -3 equals -33, and 11 + (-3) equals 8. Therefore, there are no real numbers that satisfy both conditions simultaneously.
11 multiply by 11 equals 121 so the product of 121 equals 11
1210, what you do is multiply 11x11 which equals 121 and then multiply that by 10 to get your answer
220
15 and -4
The two numbers that multiply to 24 and add up to -11 are -3 and -8. When multiplied, -3 × -8 equals 24, and when added, -3 + -8 equals -11.
Well, honey, to get 55, you can multiply 5 and 11. That's all there is to it. Math doesn't have to be complicated, just like my love life.
The two numbers that add to -11 and multiply to 19 are -10 and -1. When you add them together, -10 + (-1) equals -11. When you multiply them, -10 × -1 equals 10, not 19. Therefore, there are no two real numbers that satisfy both conditions simultaneously.
The numbers that multiply to give you 121 and add to give you 8 are 11 and -11. When multiplied, 11 × -11 equals 121; however, they do not add up to 8. The correct numbers that meet both conditions are 11 and -3, as 11 × -3 equals -33, and 11 + (-3) equals 8. Therefore, there are no real numbers that satisfy both conditions simultaneously.
You can set this problem up like this: 48/4 = y/11 Cross multiply 48*11 = 4y 528 = 4y 528 divided by 4 = 132 So when w equals 11 y equals 132
Division is the same thing as multiplication. To find the answer, you multiply 12 and 11, which equals 132. (12 x 11 = 132) 132/12=11 OR 132 ÷ 12 = 11 same thing as 12 x 11 = 132
The two numbers that multiply to -11 and add to -5 are -11 and 1. When you multiply -11 and 1, the result is -11. When you add them together, -11 + 1 equals -10, not -5. Therefore, there are no two real numbers that satisfy both conditions.
This is easy. All you need to know is your 11 times table. 11 times 11 equals 121