The equation of such a line is [ Y = -4x plus any number].
q2
-4
Rearranging the original equation, we get y=-(2/3)x+12. Since 12 is the constant, this is the point that the line of this equation will cut the y-axis if x=0. Therefore, -(2/3) is the gradient and for an equation to produce a parallel line, the gradient must be equal. Summing up, y=-(2/3)+c (where c equals any real number) would be parallel
4x+y = 14 will be parallel to the above equation because the slope or gradient remains the same but the y intercept changes.
5
[ y = plus or minus any number ] is parallel to the x-axis.
(Y = -2x plus or minus any number) is parallel to (Y = -2x + 5) .
Any equation of the form 2x + 3y = c, where c is a constant value, represents a line parallel to the given line 2x + 3y = 12.
I assume the question should be y = -2x + 5? The equation of a line that is parallel to that line is any line that begins 7 = -2x ... after the -2x any number may be added or subtracted. Parallel lines have the same slope. In the original equation, the slope is -2.
The equation of such a line is [ Y = -4x plus any number].
q2
-4
Rearranging the original equation, we get y=-(2/3)x+12. Since 12 is the constant, this is the point that the line of this equation will cut the y-axis if x=0. Therefore, -(2/3) is the gradient and for an equation to produce a parallel line, the gradient must be equal. Summing up, y=-(2/3)+c (where c equals any real number) would be parallel
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
4x+y = 14 will be parallel to the above equation because the slope or gradient remains the same but the y intercept changes.
If you mean: y = -23x+3 then the parallel equation is y = -23x+164