Q: What force needed to give 500 newtons this acceleration 3.00 plus 3 meters per second squared?

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F = m a = (976) (2.5) = 2,440 newtons

Force = mass * acceleration and acceleration is in units of meters per second squared. I will assume you mean this. m/s2 Force = (1800 kg)(4 m/s2) = 7200 Newtons ----------------------

Force = mass * acceleration Force = (3000 kg)*(2 m/s^2) = 6000 Newtons ---------------------- ( that is 6000 times the force needed to push in a doorbell, on average )

66.8

By Newton's Second Law: F = ma, and since both mass (10kg) and acceleration (5 m/s2) is provided. The magnitude of the force needed is simply 10 x 5 = 50 kgm/s2 or 50 newtons.

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F = m a = (976) (2.5) = 2,440 newtons

Force = mass * acceleration and acceleration is in units of meters per second squared. I will assume you mean this. m/s2 Force = (1800 kg)(4 m/s2) = 7200 Newtons ----------------------

Force = mass * acceleration Force = (3000 kg)*(2 m/s^2) = 6000 Newtons ---------------------- ( that is 6000 times the force needed to push in a doorbell, on average )

fROM nEWTON'S 2ND LAW, F = ma where m = mass and a = acceleration F = 6000 x 2.2 = 13,200 kg-m/sec2 = 13200 Newtons

The force needed can be calculated using the formula: Force = mass x acceleration. Plugging in the values, Force = 1000 kg x 3 m/s^2 = 3000 N. Therefore, 3000 Newtons of force is needed to accelerate a 1000-kg car at a rate of 3 meters per second squared.

F = (mass) x (acceleration) = (55) x (15) = 825 newtons.

In SI units: Force in N (Newton = kg ms/s2); Acceleration in m/s2Other systems of measurement:In cgs units: Force in dyn (Dyne = g cm/s2); Acceleration in cm/s2Also force is stated in kp (kilopond or kilogram-force) - the force exerted by earth's gravity on 1 kg.In Imperial units: Force in lbf (pound-force) - the force exerted on earth's gravity on 1 lb.and in pdl (poundal = lb ft/s2); Acceleration in ft/s2

66.8

Force = Mass * Acceleration = 1 * 2 = 2 Newtons

By Newton's Second Law: F = ma, and since both mass (10kg) and acceleration (5 m/s2) is provided. The magnitude of the force needed is simply 10 x 5 = 50 kgm/s2 or 50 newtons.

What is the acceleration of a runner whose mass is 50 kg if the runner is being pushed along by a force of 100 newtons?