As all the required numbers are even, we can identify the smallest value number as 2a, then the other three consecutive even numbers are (2a + 2), (2a + 4) and (2a + 6).
The sum of these four numbers is, 2a + (2a + 2) + (2a + 4) + (2a + 6) = 8a + 12
Then, 8a + 12 = 412
8a = 412 - 12 = 400
2a = 400 / 4 = 100
The four consecutive even numbers are 100, 102, 104 & 106.
NOTE : In this problem the choice of 'a' as the smallest value number would have achieved the correct answer but in other situations such a choice could have resulted in 4 consecutive ODD numbers being found. When in doubt use 2a or similar to clearly identify that the number is even.
Four hundred and twelve.
412 + 80,000 or 80,000 + 412 It equals 80,412.
Standard Form: Four hundred twelve.
Yes, it would help when rounding. I rounded 0.8 up to 1 and 412 down to 400. 1*400=400 The actual answer: 0.8*412=329.6
167 363 429 512 579579 - 167 = 412Yes, the range of the set of numbers is 412.
If both 116 and 412 are included, then 264.
412, 414, 416, 418, 420, 422, 424, 426. Excluding the 412 and 426, there are 6 even numbers.
357 billion 412 million in numbers = 357,412,000,000
The LCM of 412 and 30 is 6180
2, 103
Four hundred and twelve.
1 x 412, 2 x 206, 4 x 103
51.5
412 + 80,000 or 80,000 + 412 It equals 80,412.
Standard Form: Four hundred twelve.
Yes, it would help when rounding. I rounded 0.8 up to 1 and 412 down to 400. 1*400=400 The actual answer: 0.8*412=329.6
167 363 429 512 579579 - 167 = 412Yes, the range of the set of numbers is 412.