As all the required numbers are even, we can identify the smallest value number as 2a, then the other three consecutive even numbers are (2a + 2), (2a + 4) and (2a + 6).
The sum of these four numbers is, 2a + (2a + 2) + (2a + 4) + (2a + 6) = 8a + 12
Then, 8a + 12 = 412
8a = 412 - 12 = 400
2a = 400 / 4 = 100
The four consecutive even numbers are 100, 102, 104 & 106.
NOTE : In this problem the choice of 'a' as the smallest value number would have achieved the correct answer but in other situations such a choice could have resulted in 4 consecutive ODD numbers being found. When in doubt use 2a or similar to clearly identify that the number is even.
Chat with our AI personalities
Four hundred and twelve.
412 + 80,000 or 80,000 + 412 It equals 80,412.
Standard Form: Four hundred twelve.
Yes, it would help when rounding. I rounded 0.8 up to 1 and 412 down to 400. 1*400=400 The actual answer: 0.8*412=329.6
167 363 429 512 579579 - 167 = 412Yes, the range of the set of numbers is 412.