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As all the required numbers are even, we can identify the smallest value number as 2a, then the other three consecutive even numbers are (2a + 2), (2a + 4) and (2a + 6).

The sum of these four numbers is, 2a + (2a + 2) + (2a + 4) + (2a + 6) = 8a + 12

Then, 8a + 12 = 412

8a = 412 - 12 = 400

2a = 400 / 4 = 100

The four consecutive even numbers are 100, 102, 104 & 106.

NOTE : In this problem the choice of 'a' as the smallest value number would have achieved the correct answer but in other situations such a choice could have resulted in 4 consecutive ODD numbers being found. When in doubt use 2a or similar to clearly identify that the number is even.

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Q: What four consecutive even numbers have a sum of 412?
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