Oh, what a delightful little puzzle we have here! To find a four-digit number that is divisible by both 8 and 9, we can look for a number that is divisible by their least common multiple, which is 72. So, let's find a multiple of 72 that is a four-digit number, like 1008. Such a harmonious number, don't you think?
1249 x 8 = 9992
1008 is one such.
1200 = 3*5*8*10
The number 72, when divided by 9, the correct answer is 8. This is not a four digit numeric. To express 72 as a four digit numeric, write 0072. 0072 / 9 = 8.
Yes. To check divisibility by 8 add the units digit to twice the ten's digit to four times the hundred's digit; if this sum is divisible by 8, so is the original number: 4 + 2x4 + 4x3 = 4 + 8 + 12 = 24 which is divisible by 8, so 110344 is also divisible by 8.
4444
1249 x 8 = 9992
i do not know but i think it 480
1008 is one such.
1200 = 3*5*8*10
There is no answer because for a number to be divisible by 8, it would end in an even number and therefore be divisible by 2.
The number 72, when divided by 9, the correct answer is 8. This is not a four digit numeric. To express 72 as a four digit numeric, write 0072. 0072 / 9 = 8.
Yes. To check divisibility by 8 add the units digit to twice the ten's digit to four times the hundred's digit; if this sum is divisible by 8, so is the original number: 4 + 2x4 + 4x3 = 4 + 8 + 12 = 24 which is divisible by 8, so 110344 is also divisible by 8.
There is no 5 digit number which is divisible by 23456910 (an 8-digit number)..
No. To test if a number is divisible by 8: * first all multiples of 8 are even, so the number must be even; * then: add 4 times the hundreds digit to twice the tens digit to the ones digit - if this sum is divisible by 8, then so is the original number. As the test can be applied to the sum, repeating this summing until a single digit remains, only if this single digit is 8 is the original number divisible by 8. For 100: 4x1 + 2x0 + 0 = 4 which is not 8, so 100 is not divisible by 8.
To be divisible by 36 the number must be divisible by 9 (and 4). To be divisible by 9, the sum of the digits must be divisible by 9. 5 + 5 = 10 → need an extra 8 → A + B = 8.
8888