There are infinitely many possible sets. Some examples:
1, -1, -1, 720
1, 2, 3, 120
10, 20, 30, 0.12
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To find four numbers that multiply to 720, one possible combination is 2, 3, 4, and 30, since (2 \times 3 \times 4 \times 30 = 720). Another combination could be 2, 5, 6, and 6, since (2 \times 5 \times 6 \times 6 = 720). There are multiple sets of numbers that can yield the product of 720.
To find four numbers that multiply together to equal 720, you can use the factors of 720. One combination is 4, 3, 5, and 12, since (4 \times 3 \times 5 \times 12 = 720). Another possible set is 8, 9, 10, and 1, as (8 \times 9 \times 10 \times 1 = 720). There are multiple combinations, depending on how you choose to factor the number.
2880
360 x 2 = 720
Well, isn't that a happy little math problem! To find three numbers that multiply to 720, we can start by breaking down 720 into its prime factors: 2 x 2 x 2 x 3 x 3 x 5. Then, we can group these factors into three numbers, like this: 2 x 2 x 180, which equals 720. So, the three numbers are 2, 2, and 180.