The prime factorization of 294 is 2 * 3 * 7 * 7. Therefore, the four prime numbers that multiply to make 294 are 2, 3, 7, and 7.
They are: 3*3*5*5 = 225
They are: 2*5*5*5 = 250
The prime factorization of 225 is (3^2 \times 5^2). To express this as a product of four prime numbers, we can write it as (3 \times 3 \times 5 \times 5). Thus, the four prime numbers that multiply to make 225 are 3, 3, 5, and 5.
The prime factorization of 735 is (3 \times 5 \times 7 \times 7). However, since 7 is repeated, it does not constitute four distinct prime numbers. The four prime numbers that multiply to give 735, including repetition, are 3, 5, and two instances of 7. Thus, the prime numbers are 3, 5, 7, and 7.
The prime factorization of 294 is 2 * 3 * 7 * 7. Therefore, the four prime numbers that multiply to make 294 are 2, 3, 7, and 7.
They are: 3*3*5*5 = 225
They are: 2*5*5*5 = 250
The prime factorization of 225 is (3^2 \times 5^2). To express this as a product of four prime numbers, we can write it as (3 \times 3 \times 5 \times 5). Thus, the four prime numbers that multiply to make 225 are 3, 3, 5, and 5.
The prime factorization of 735 is (3 \times 5 \times 7 \times 7). However, since 7 is repeated, it does not constitute four distinct prime numbers. The four prime numbers that multiply to give 735, including repetition, are 3, 5, and two instances of 7. Thus, the prime numbers are 3, 5, 7, and 7.
The three prime numbers which multiply to make 231 are 3 x 7 x 11.
13*31=403 13 and 31 are prime numbers.
You'll nee four. 3 x 3 x 3 x 11
111 = 3*37
The prime factorization of 1050 is (2 \times 3 \times 5^2 \times 7). The distinct prime numbers that multiply to give 1050 are 2, 3, 5, and 7. Since there are only four distinct prime factors, it’s not possible to identify five different prime numbers that multiply to 1050. Therefore, the answer includes only these four primes: 2, 3, 5, and 7.
225 cannot be factorised into the product of only 3 prime numbers.
They are: 29*43 = 1247