Let f = 3.333...Then 10*f = 33.333... Subtracting the first from the second, 9f = 30 So f = 30/9 = 10/3.
Suppose f = 2.222...then 10 f = 22.222... Subtracting the first from the second: 9f = 20 So f = 20/9
Suppose f = 0.5777... then 10 f = 5.7777... so that 9 f = 5.2 and so f = 5.2/9 = 52/90 = 26/45
Suppose f = -0.555...then 10*f = -5.555... Subtracting the first from the second gives: 9*f = -5 and therefore, f = -5/9.
One tenth (1/10) = 10%. Think of Percent as 'per hundred', so to find a percentage, do this: F = P% = P/100, where F is the fraction, and P is the percentage.You are given F, so solve for P. Rearrange and you have P = 100 x F, so we have P = [100 x (1/10)] = 10.
This is an interesting and important fraction!Let f = 0.9999...Then 10*f = 9.9999...Subtracting the first from the second gives 9*f = 9So that f = 9/9 = 1.
Let f = 3.333...Then 10*f = 33.333... Subtracting the first from the second, 9f = 30 So f = 30/9 = 10/3.
Let F = 1.7666.... then 10*F = 17.6666.... So 10*F - F = 17.6666.... - 1.7666... 9*F = 15.9 F = 15.9/9 = 159/90 = 53/30
Suppose f = 1.1 recurring then 10f = 11.1 recurring Subtracting the first from the second: 9f = 10 or f = 10/9
Let f = 0.4444...Then 10*f = 4.4444...Subtracting the first from the second gives 9*f = 4So that f = 4/9.
Suppose f = 2.222...then 10 f = 22.222... Subtracting the first from the second: 9f = 20 So f = 20/9
A fraction f is greater than a fraction g if (f - g) is positive.
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Let f = 0.8888...Then 10*f = 8.8888...Subtracting the first from the second gives 9*f = 8So that f = 8/9.
Suppose f = 0.5777... then 10 f = 5.7777... so that 9 f = 5.2 and so f = 5.2/9 = 52/90 = 26/45
Suppose f = -0.555...then 10*f = -5.555... Subtracting the first from the second gives: 9*f = -5 and therefore, f = -5/9.
One tenth (1/10) = 10%. Think of Percent as 'per hundred', so to find a percentage, do this: F = P% = P/100, where F is the fraction, and P is the percentage.You are given F, so solve for P. Rearrange and you have P = 100 x F, so we have P = [100 x (1/10)] = 10.