Assume this problem deals with multiples of the numbers. The objective is vague, but I'm pretty sure of what is asked here.
If we want to find the gcd of these terms, factor out each term and select the prime factor with the least exponent. Finally, evaluate the product of all prime factors. For instance:
12 = 3 x 2²
= 2² x 30 x 110
44 = 11 x 2²
= 2² x 30 x 11
Therefore, the gcd is 2² = 4!
44
It is: 4 that is the gcf of 12 and 44
No. 12 and 44 have a common factor greater than 1: hcf(12, 44) = 4 → 12/44 = 3x4/11x4 = 3/11
12/44 = 3/11
1, 2, 4, 22, and 44 all go into 44.
It goes: 44/12 = 3 times with a remainder of 8
From 44/X = 100 we have X = 44/100 goes into 44 to make 100.
Well, honey, 12 goes into 530 a grand total of 44 times. That's right, 44 times. So, if you're looking to divide up that 530 into nice, neat little 12-sized chunks, you'll have 44 of 'em. Hope that helps, sugar!
Well, isn't that a happy little math problem! Let's see, if we take 44 and divide it by 16, we find that 16 goes into 44 two times with a remainder of 12. Remember, there are no mistakes in math, just happy little accidents.
To determine how many times 44 goes into 100, you divide 100 by 44. The result is approximately 2.2727. Since we cannot have a fraction of a division in this context, we would say that 44 goes into 100 a total of 2 times with a remainder of 12.
-44
No. 44 is not evenly divisible by 12.
44
It is: 4 that is the gcf of 12 and 44
No. 12 and 44 have a common factor greater than 1: hcf(12, 44) = 4 → 12/44 = 3x4/11x4 = 3/11
12/44 = 3/11
1, 2, 4, 22, and 44 all go into 44.