Any of its factors
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693 is evenly divisible by 3. You can tell that at a glance because every one of its digits is evenly divisible by 3.
It goes: 693/32 = 21 times with a remainder of 21
1, 3, 7, 9, 11, 21, 33, 63, 77, 99, 231, 693
1 goes into 5 and 4 evenly.
The only whole number that goes into "7" evenly is 7.The number "7" also goes into the number "70" evenly (10x7=70).