The square root of 8 is irrational and real.
It can't be expressed as a whole number. The square root of two is irrational, and the product of an irrational number and a rational number is also irrational. So 8*sqrt(2) is irrational.
No it's 8, which is not irrational.
No. sqrt(8) is irrational sqrt(2) is irrational but sqrt(8) /sqtr(2) = sqrt(4) = ±2 is not irrational.;
It is rational.
Negative 8, which can also be written as -8, is a irrational l number. How? Irrational numbers are numbers that are not rational, and -8 is not rational.
Sometimes yes, sometimes no. sqrt(2) x sqrt(8) = 4 rational sqrt(2) x sqrt(3) = sqrt(6) irrational
8 is not an irrational number because it can be expressed as a fraction in the form of 8/1 and so therefore it is a rational number
The square root of 8 is irrational and real.
It can't be expressed as a whole number. The square root of two is irrational, and the product of an irrational number and a rational number is also irrational. So 8*sqrt(2) is irrational.
It is an irrational number
3/8 is rational, it can't be irrational.
No it's 8, which is not irrational.
8 is a whole number, an integer, rational and real.
8 is an integer, which, by definition, are not irrational. In particular, an irrational number is a number that cannot be written in the form p/q for p and q both integers. However, since 8 clearly is equal to 8k/k for any integer k (and for that matter any nonzero number k), 8 is not irrational
The square root of 8 is an irrational number because it cannot be represented as a fraction of two integers.
No. sqrt(8) is irrational sqrt(2) is irrational but sqrt(8) /sqtr(2) = sqrt(4) = ±2 is not irrational.;