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Let ABCD be a rectangleAB = CD = 9 ftBC = DA(AB)x(BC) = 54 ftBC = 54/(AB) = 54/9 = 6 ftperimeter = (AB)+(BC)+(CD)+(DA) = 2(AB)+2(BC) = 2x9+2x6 = 30 ft
739 BC happened 739 years before the birth of Christ, and 465 AD happened 465 years after his death.
since BC=1/2 AC you take half of 54 then solve the equation. 3x^2=54/2 3x^2=27 x^2=9 x=3
It stands for "circa" which means "about". So if it said thar the war happened "c 1340" it means it happened in about the year 1340.
54, 54, 54, 54, 54, 54, 54, 54, 54, 84 The median is clearly 54. The mean is ((54*9)+84)/10 = 57.