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60b2 you multiply the coefficients then the exopnients 5b1 (next to variables there are invisible exonients) x 12b1 ______ 60b2 (when multiplying like variables you add the exponients)
X2 * 2X= 2X3======multiply coefficients and add exponents ( all variables have a 1 as implied exponent )
When you multiply two variables with different exponents, the exponents are added. For example, if you multiply x^2 by x^3, the result is x^(2+3) = x^5. Similarly, if you multiply x^3 by x^(-2), the result is x^(3+(-2)) = x^1 = x.
They have the same form for any variables, but the numerical coefficients can be different.
-.12
Coefficients don't 'stand' for anything. They are numbers which multiply variables. For instance, in the expression 3 x + 2, three is the coefficient of x.
60b2 you multiply the coefficients then the exopnients 5b1 (next to variables there are invisible exonients) x 12b1 ______ 60b2 (when multiplying like variables you add the exponients)
X2 * 2X= 2X3======multiply coefficients and add exponents ( all variables have a 1 as implied exponent )
Eliminate the variables that have equal coefficients but opposite in sign.x + 2y = 103x - 2y = 14Or you can work to have one of the variables with equal coefficients but opposite in sign such as:3x + 2y = 5x + y = 2 multiply by -2 to both sides3x + 2y = 5-2x - 2y = -4
parameters
You are dividing two monomials. Divide the coefficients of the variables, and multiply by the division of the variables. 7b/9b = 7/9 x b/b = 7/9 x 1 = 7/9
We would need to have the list of correlation coefficients to respond to this question.
yes
Only subtract, if they are pointers to the same type. Example:double coefficients [12], *p= &coefficients[3], *q= &coefficients[4];printf ("q-p=%d\n", (int)(q-p));Note: The result is 1, not sizeof (double)
When you multiply two variables with different exponents, the exponents are added. For example, if you multiply x^2 by x^3, the result is x^(2+3) = x^5. Similarly, if you multiply x^3 by x^(-2), the result is x^(3+(-2)) = x^1 = x.
-85-6x=91+2x
Yes, if they are in common for all the terms.