60b2 you multiply the coefficients then the exopnients 5b1 (next to variables there are invisible exonients) x 12b1 ______ 60b2 (when multiplying like variables you add the exponients)
X2 * 2X= 2X3======multiply coefficients and add exponents ( all variables have a 1 as implied exponent )
To find the product of X and 7X, you multiply the coefficients (numbers in front of the variables) and then multiply the variables together. In this case, 1 (implied coefficient of X) times 7 times X equals 7X^2. So, X times 7X is equal to 7X^2.
When you multiply two variables with different exponents, the exponents are added. For example, if you multiply x^2 by x^3, the result is x^(2+3) = x^5. Similarly, if you multiply x^3 by x^(-2), the result is x^(3+(-2)) = x^1 = x.
They have the same form for any variables, but the numerical coefficients can be different.
Coefficients don't 'stand' for anything. They are numbers which multiply variables. For instance, in the expression 3 x + 2, three is the coefficient of x.
60b2 you multiply the coefficients then the exopnients 5b1 (next to variables there are invisible exonients) x 12b1 ______ 60b2 (when multiplying like variables you add the exponients)
X2 * 2X= 2X3======multiply coefficients and add exponents ( all variables have a 1 as implied exponent )
Eliminate the variables that have equal coefficients but opposite in sign.x + 2y = 103x - 2y = 14Or you can work to have one of the variables with equal coefficients but opposite in sign such as:3x + 2y = 5x + y = 2 multiply by -2 to both sides3x + 2y = 5-2x - 2y = -4
parameters
2a x 3b = 6ab
To find the product of X and 7X, you multiply the coefficients (numbers in front of the variables) and then multiply the variables together. In this case, 1 (implied coefficient of X) times 7 times X equals 7X^2. So, X times 7X is equal to 7X^2.
To find the product of 8x and 2x, you multiply the coefficients (8 and 2) to get 16, and then multiply the variables (x and x) to get x^2. Therefore, 8x * 2x equals 16x^2.
yes
We would need to have the list of correlation coefficients to respond to this question.
You are dividing two monomials. Divide the coefficients of the variables, and multiply by the division of the variables. 7b/9b = 7/9 x b/b = 7/9 x 1 = 7/9
Only subtract, if they are pointers to the same type. Example:double coefficients [12], *p= &coefficients[3], *q= &coefficients[4];printf ("q-p=%d\n", (int)(q-p));Note: The result is 1, not sizeof (double)