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What happens to the coefficients when you multiply variables?
When you multiply variables together, the coefficients of those variables are multiplied as well. For example, if you have two variables (a) and (b) with coefficients (c) and (d), respectively, multiplying them results in a new expression with a coefficient of (cd) for the product (ab). Therefore, the overall coefficient of the resulting term is the product of the original coefficients.
What is 6c x 6e?
To multiply the expressions (6c) and (6e), you multiply the coefficients and the variables separately. The coefficients (6) and (6) multiply to give (36), and the variables (c) and (e) combine to give (ce). Therefore, (6c \times 6e = 36ce).
What is 5b x 12b?
60b2 you multiply the coefficients then the exopnients 5b1 (next to variables there are invisible exonients) x 12b1 ______ 60b2 (when multiplying like variables you add the exponients)
What is x2 multiplied by 2x?
X2 * 2X= 2X3======multiply coefficients and add exponents ( all variables have a 1 as implied exponent )
How do you multiply 4n and 2n?
Well, honey, it ain't rocket science. To multiply 4n by 2n, you simply multiply the coefficients (4 and 2) to get 8, and then multiply the variables (n and n) to get n^2. Put 'em together and you've got 8n^2. Easy peasy lemon squeezy!
What happens to the coefficients when you multiply variables?
When you multiply variables together, the coefficients of those variables are multiplied as well. For example, if you have two variables (a) and (b) with coefficients (c) and (d), respectively, multiplying them results in a new expression with a coefficient of (cd) for the product (ab). Therefore, the overall coefficient of the resulting term is the product of the original coefficients.
What is 6c x 6e?
To multiply the expressions (6c) and (6e), you multiply the coefficients and the variables separately. The coefficients (6) and (6) multiply to give (36), and the variables (c) and (e) combine to give (ce). Therefore, (6c \times 6e = 36ce).
What do coefficients stand for?
Coefficients don't 'stand' for anything. They are numbers which multiply variables. For instance, in the expression 3 x + 2, three is the coefficient of x.
What is 5b x 12b?
60b2 you multiply the coefficients then the exopnients 5b1 (next to variables there are invisible exonients) x 12b1 ______ 60b2 (when multiplying like variables you add the exponients)
What is x2 multiplied by 2x?
X2 * 2X= 2X3======multiply coefficients and add exponents ( all variables have a 1 as implied exponent )
How do you multiply 4n and 2n?
Well, honey, it ain't rocket science. To multiply 4n by 2n, you simply multiply the coefficients (4 and 2) to get 8, and then multiply the variables (n and n) to get n^2. Put 'em together and you've got 8n^2. Easy peasy lemon squeezy!
What is 10x times 20x is?
The expression (10x \times 20x) can be simplified by multiplying the coefficients and the variables separately. The coefficients (10) and (20) multiply to give (200), and the variables (x) and (x) combine to give (x^2). Therefore, (10x \times 20x = 200x^2).
What is the key to using the elimination method to find variable terms in the two equations that have equal or opposite coefficients?
Eliminate the variables that have equal coefficients but opposite in sign.x + 2y = 103x - 2y = 14Or you can work to have one of the variables with equal coefficients but opposite in sign such as:3x + 2y = 5x + y = 2 multiply by -2 to both sides3x + 2y = 5-2x - 2y = -4
What is a constant value that are not coefficients of variables to equations?
parameters
What is X times 7x?
To find the product of X and 7X, you multiply the coefficients (numbers in front of the variables) and then multiply the variables together. In this case, 1 (implied coefficient of X) times 7 times X equals 7X^2. So, X times 7X is equal to 7X^2.
What is 8x times 2x?
To find the product of 8x and 2x, you multiply the coefficients (8 and 2) to get 16, and then multiply the variables (x and x) to get x^2. Therefore, 8x * 2x equals 16x^2.
Could you multiply constants with coefficients?
yes
