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What happens to density when increasing mass and holding volume constant?
Wiki User
∙ 13y ago
The density will increase.
Wiki User
∙ 13y ago
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How is the density affected by increasing volume while holding the mass constant?
(mass) Density is mass/volume, so increasing the volume with mass held constant will decrease the density.
Why would you want to find volume of any object?
If you want to determine the density of an object, you would measure the mass and volume, then divide mass/volume to determine density. This can help determine the composition of the object. For example, if you find a rock that looks like a gold nugget. The density of gold is a known value, so one of the tests in determining if you are holding real gold would be to determine the density of your rock. This is one example. Another (maybe more 'real world' for you). Shipping and cargo companies measure the volume of packages as they go by on the conveyor belt, so that they can figure how many will fit in a particular truck.
When was Holding You Down - Goin' in Circles - created?
Holding You Down - Goin' in Circles - was created on 2010-07-10.
How is a stapler a wedge?
by holding it in place
Why you cannot hold a bucket of water without holding it?
"Can't hold without holding it" doesn't make sense. Either you hold it, or you don't. Tertium non datur.
How is the density affected by increasing the mass whiule holding the volume constant?
Holding volume constant while increasing mass will increase density. density = mass / volume
How is the density affected by increasing volume while holding the mass constant?
(mass) Density is mass/volume, so increasing the volume with mass held constant will decrease the density.
How is the density affected by increasing the mass while holding the volume constant?
it doesnt change
How is density affected by increasing the mass while holding the volume constant?
Increasing the mass while holding the volume constant will increase the density of the object. Density is calculated by dividing mass by volume, so as mass increases with constant volume, the resulting density will also increase.
How is density affected by increasing the volume while holding the mass constant?
Density would be reduced. Density is a measure of the mass per unit volume. For example, 10 particles per cubic mL. If you made the vollume bigger but kept the mass the same, there would be more room for the ten particles to spread out, they'd be further away from each other so the density would be less.
When holding your breath what does it do to your density?
It makes your density thicken.
Why temperature becomes constant at melting and boiling point?
At the melting point, the temperature remains constant because the energy being absorbed is utilized to overcome the intermolecular forces holding the solid together, rather than increasing the temperature. Similarly, at the boiling point, the temperature remains constant as the energy is used to break the intermolecular bonds holding the liquid together, allowing the substance to transition into the gas phase.
What happens to an objects density when mass is the same and volume is less?
When the volume of an object decreases while its mass remains the same, the object's density increases. This is because density is defined as mass divided by volume, so if mass stays constant while volume decreases, the quotient (density) increases.
What dose inflated mean?
"Inflated" means "artificially high" in general usage. In economics, it refers to the process by which, holding the real value of goods constant, their nominal values increases. This translates into increasing price levels.
What is the name of the assumption that means holding all things constant?
ceteris paribus
Can you transition boiled water directly to vapor under a very low temperature?
Sure, reduce the pressure.Boiling can be produced either by:raising temperature while holding constant pressurelowering pressure while holding constant temperature
What happens when you are held to answer?
It completely depends on WHO or WHAT it is that that is "holding you to answer."
