The probability of getting at least one tail in a flip of six coins is the same as the probability of not getting all heads, which is 1 - (0.56), or 0.984375.
Number of possible outcomes of one coin = 2Number of possible outcomes of six coins = 2 x 2 x 2 x 2 x 2 x 2 = 64Number of possible outcomes with six heads = 1Probability of six heads = 1/64Probability of not six heads = at least one tails = 63/64 = 98.4375%
Heads comes up half the time, sis one time in six tosses so the combined odds of heads and six is 1/2 x 1/6 = 1/12, one time in 12.
The probability that you will toss five heads in six coin tosses given that at least one is a head is the same as the probability of tossing four heads in five coin tosses1. There are 32 permutations of five coins. Five of them have four heads2. This is a probability of 5 in 32, or 0.15625. ----------------------------------------------------------------------------------- 1Simplify the problem. It asked about five heads but said that at least one was a head. That is redundant, and can be ignored. 2This problem was solved by simple inspection. If there are four heads in five coins, this means that there is one tail in five coins. That fact simplifies the calculation to five permutations exactly.
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The probability of getting at least one tail in a flip of six coins is the same as the probability of not getting all heads, which is 1 - (0.56), or 0.984375.
No idea
The requirement that one coin is a head is superfluous and does not matter. The simplified question is "what is the probability of obtaining exactly six heads in seven flips of a coin?"... There are 128 permutations (27) of seven coins, or seven flips of one coin. Of these, there are seven permutations where there are exactly six heads, i.e. where there is only one tail. The probability, then, of tossing six heads in seven coin tosses is 7 in 128, or 0.0546875.
Number of possible outcomes of one coin = 2Number of possible outcomes of six coins = 2 x 2 x 2 x 2 x 2 x 2 = 64Number of possible outcomes with six heads = 1Probability of six heads = 1/64Probability of not six heads = at least one tails = 63/64 = 98.4375%
A six tail is either one of naruto kyubii forms or the six tail slug that's sealed into ukataka's body
you are looking for the probability of getting one tail, two,......., and six this equivalent to saying 1 - the probability of not getting any tails (or getting 6 heads = (1/2)^6). P(X>=1) = 1 - (1/2)^6=
In Greek mythology, Scylla was a sea monster with twelve tentacle-like legs and six dog-like heads. She lived on one side of a narrow strait opposite the whirlpool Charybdis, posing a threat to passing ships. Sailors had to navigate carefully between the two dangers.
The longest tiger measured to be309 centimeters long.
Heads comes up half the time, sis one time in six tosses so the combined odds of heads and six is 1/2 x 1/6 = 1/12, one time in 12.
Scylla has four eyes, six long necks equipped with grisly heads(each with three rows of sharp teeth), twelve tentacle-like legs, and a cat's tail and with four to six dog heads hanging from her waist.
Scylla was a grotesque monster, with six long necks equipped with grisly heads, each of which contained three rows of sharp teeth. Her body consisted of twelve tentacle-like legs and a cat's tail and with four to six dog-heads ringing her waist.