Assuming the dimensions of the square pan is 8 by 8 by 2, the volume is:
8 x 8 x 2 = 128 cubic inches
Volume of circle pan is: pi × r2 × h where pi is 3.14, r is half the diameter or 4 inches and h = 2
3.14 x 4 x 4 x 2 = 100.48 cubic inches
Assuming a circular pool, divide the diameter by 2 to get the radius, then use the formula for the area of a circle. The depth is not relevant for this problem.
The area of a hole 4 feet in diameter and 19 feet deep is: 76 square feet. (4 x 19 = 76).
It depends upon whether the 24' is the radius, diameter or circumference.
To calculate the amount of sand needed for a 14-foot diameter circle that is 3 inches deep, first convert the diameter to radius: 14 feet ÷ 2 = 7 feet. The area of the circle is π (approximately 3.14) times the radius squared: π × (7 feet)² ≈ 153.94 square feet. Then, multiply the area by the depth in feet (3 inches = 0.25 feet): 153.94 sq ft × 0.25 ft = approximately 38.49 cubic feet of sand needed.
a 4 feet diameter tank holds 94 gallons/foot. Therefore 94 x 3 =282 gallons
Assuming a circular pool, divide the diameter by 2 to get the radius, then use the formula for the area of a circle. The depth is not relevant for this problem.
The area of a hole 4 feet in diameter and 19 feet deep is: 76 square feet. (4 x 19 = 76).
A tank this size holds up to 3,004(3,003.967872) gallons.
Volume = pi * radius^2 * height
It is not possible to answer the question since the dimensions for the diameter are not given. 15 WHAT? Feet, yards? something else?
Without depth, the circle is a flat figure without volume ... zero cubic units.
Assuming the 28 feet refers to the diameter of the circle, the answer is 1231.5 cubic feet, approx.
It depends upon whether the 24' is the radius, diameter or circumference.
My swimming pool holds 1250 gallons. It is 12 feet diameter and 3 feet deep.
110ftx8ins
if you mean a 30 foot diameter circle, then pi x 152 x 3 = 2119.5 cubic feet of dirt
a 4 feet diameter tank holds 94 gallons/foot. Therefore 94 x 3 =282 gallons