Just substitute 4 in for X.
13 - 2(4)
13 - 8
= 5
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The expression ( \log_5 625 ) represents the exponent to which the base 5 must be raised to obtain 625. Since ( 625 = 5^4 ), it follows that ( \log_5 625 = 4 ). Thus, the value of the expression is 4.
The expression (2x - 4) represents a linear equation where the value depends on the variable (x). To determine a specific value, you need to substitute a specific value for (x). For example, if (x = 3), then (2x - 4 = 2(3) - 4 = 6 - 4 = 2). Without a specific value for (x), the expression remains variable.
Say you have an algebraic expression y = 3x +4 For a given value of x = 5 substitute that number in place of x in the expression, so in this case y = 3(5) + 4 = 19
Evaluate the following expression to 4*(12.25-4)/(9+2)
To determine the value expression when ( x = -2 ), you need to substitute -2 into the given expression. For example, if the expression is ( 2x + 3 ), substituting -2 gives ( 2(-2) + 3 = -4 + 3 = -1 ). The specific value will depend on the expression you have; please provide that for a more accurate answer.
in this given variable in this is x.
It is an algebraic expression that can be simplified depending on the plus or minus value of 4
The expression ( \log_5 625 ) represents the exponent to which the base 5 must be raised to obtain 625. Since ( 625 = 5^4 ), it follows that ( \log_5 625 = 4 ). Thus, the value of the expression is 4.
-2
4
1/4
(21-3)times(7+4)
To find the value of y in the expression 15y-4 = 41, you need to isolate y. Start by adding 4 to both sides of the equation to get 15y = 45. Then, divide both sides by 15 to solve for y, which equals 3. Therefore, the value of y in the expression 15y-4 when it equals 41 is 3.
4
The expression (2x - 4) represents a linear equation where the value depends on the variable (x). To determine a specific value, you need to substitute a specific value for (x). For example, if (x = 3), then (2x - 4 = 2(3) - 4 = 6 - 4 = 2). Without a specific value for (x), the expression remains variable.
7
To find the value of (n-2)^2 + n-1 when n=4, we simply substitute 4 for n in the expression: (n-2)^2 + n-1 When we do this, the expression becomes: (4-2)^2 + 4-1 Now we need to simplify the expression within the parentheses first. The expression within the parentheses is (4-2)^2, which means we need to subtract 2 from 4 and then square the result. So, we get: 2^2 Which equals 4. Now we can substitute this value back into the original expression to get: 4 + 4-1 Next, we simplify the expression 4-1, which equals 3. So, the expression becomes: 4 + 3 And we can simplify that further to get: 7 So, when n=4, the value of (n-2)^2 + n-1 is 7