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How do you caluculate the GCD of two prime numbers?
Let p1 and p2 be the two prime numbers. Because they are prime, their divisors are div(p1) = {1,p1} and div(p2) = {1,p2}. So GCD(p1,p2) = Greatest Common Divisor of p1 and p2 = p1 if p1 equals p2 1 if p1 is different from p2
Can a multiple of a prime number be prime?
No. Let p1 be a prime number. Let p2 be a multiple of p1 such that p2 = p1 * k. Then the factors of p2 are: 1, p1, k and p2. ==> p2 is not a prime number. Hence, a multiple of a prime number cannot be a prime number.
When the ones and tens are multiplied separately each product is called a?
The general function is:1. y = a*x+bb is irrelevant and we can be removed2. y = a*xlets split x into ones and tens3. x = tens*10 + ones /e.g. 23 = 2*10 + 34. p1 = Multiplier of the onesp2 = Multiplier of the tens5. y = tens*10*p2 + ones*p1 /according to the question6. x*a = tens*10*p2 + ones*p1 /according to 2.7. (tens*10 + ones)*a = tens*10*p2 + ones*p1 /according to 3.8. tens*10*a + ones*a = tens*10*p2 + ones*p1 /regroup9. tens*10*a - tens*10*p2 + ones*a - ones*p1 = 0 /regroup10. tens*10*(a-p2) + ones*(a-p1) = 0 /regroup11. assuming "tens" and "ones" are not 0 then (a-p2) and (a-p1) must be 012. a-p2 = 0a-p1 = 013. a = p2a = p114. a = p1 = p2the answer is: when the Multipliers of ones and tens are equal then the product is called a.
What are the condition for three points to be collinear?
p1+p2+p3=0
How do you Add 2 numbers using pointer and array in C?
#include<stdio.h> #include<conio.h> void main() { clrscr(); int i; int a[4]={1,2,3,4}; int *p1,*p2,*p3; for(i=0;i<4;i++) { p1=&a[0]; p2=&a[2]; p3=*p2-*p1; printf("\n value of p3%d",p3); } getch(); }
WHAT IS THE CORECT NAME FOR P1?
Insufficient information; this symbol has many meanings.
How do you caluculate the GCD of two prime numbers?
Let p1 and p2 be the two prime numbers. Because they are prime, their divisors are div(p1) = {1,p1} and div(p2) = {1,p2}. So GCD(p1,p2) = Greatest Common Divisor of p1 and p2 = p1 if p1 equals p2 1 if p1 is different from p2
What is the C code for preemptive priority scheduling?
#include<stdio.h> #include<conio.h> int main() { char p[10][5],temp[5]; int i,j,pt[10],wt[10],totwt=0,pr[10],temp1,n; float avgwt; clrscr(); printf("enter no of processes:"); scanf("%d",&n); for(i=0;i<n;i++) { printf("enter process%d name:",i+1); scanf("%s",&p[i]); printf("enter process time:"); scanf("%d",&pt[i]); printf("enter priority:"); scanf("%d",&pr[i]); } for(i=0;i<n-1;i++) { for(j=i+1;j<n;j++) { if(pr[i]>pr[j]) { temp1=pr[i]; pr[i]=pr[j]; pr[j]=temp1; temp1=pt[i]; pt[i]=pt[j]; pt[j]=temp1; strcpy(temp,p[i]); strcpy(p[i],p[j]); strcpy(p[j],temp); } } } wt[0]=0; for(i=1;i<n;i++) { wt[i]=wt[i-1]+et[i-1]; totwt=totwt+wt[i]; } avgwt=(float)totwt/n; printf("p_name\t p_time\t priority\t w_time\n"); for(i=0;i<n;i++) { printf(" %s\t %d\t %d\t %d\n" ,p[i],pt[i],pr[i],wt[i]); } printf("total waiting time=%d\n avg waiting time=%f",tot,avg); getch(); }
What was the original generation of pea plants in Mendel's was experiment called?
P1 or parental
What is the P in the formula P1-e?
P1-e is an expression, not a formula.
What is p1?
In genetics, in a pure-breeding population, the parental generation is the P1 generation. The off-spring of the P1 Generation is called the F1 Generation
How can you get the population growth rate?
If the old population is P1, the new population is P2, and the growth rate is G, G = (P2 - P1) ÷ P1 x 100%
What are the genotypes of the short plants in the P1 and F2 generation?
P1: tt F2: tt
Write a program t remove the occurrences of word in entered text in c?
#include#include#define n 100void del_char(char str1[n],char str2[]){char str[n],*p1,*q,i,j;p1=str1;q=str;*q=*p1;i=0;while(*p1!='\0'){{if(*p1==str2[i]){p1++;i++;if(*p1==str2[i]){p1++;i++;if(*p1==str2[i]){p1++;i++;}else{q++;}}else{q++;}}else{p1++;q++;}*q=*p1;}i=0;}printf("%s\n",str);}main(){char str1[n],str2[]={"to "};clrscr();printf("please enter a text and includ 'to':\n");gets(str1);printf("remove 'to',remaining :\n");del_char(str1,str2);getch();return 0;}Output:please enter a text and includ 'the':Write a c program to simulate the calculator using functionremove 'the',remaining :Write a c program to simulate calculator using function
Why is the budget line negatively sloped?
The budget line is negatively sloped because :- 1. MATHEMATICALLY * Given a budget line p1x1+ p2x2= M * where (x1,x2) is the budget bundle of good 1 and good 2 resp. ( i.e quantity bought of good 1 & 2 respectively) * p1 and p2 are the prevailing prices of good 1 and good 2; * M is the total budget; then, x2 = (M/p2) - (p1/p2)x1 where M/p2 is the intercept along the axis of good 2 and slope is -p1/p2 which is negative and thus there is a negative slope. 2. MEANING The slope of the budget line -(p1/p2) signifies the rate by which the consumer is ready to substitute good 1 for good 2. Consider a situation with a budget bundle (x1,x2) such that x1>x2.There would always be a point where the consumer would decline substituting good 1 for good 2 because he/she has more of good 1 and less of good 2 thus the rate of substituting declines giving a negative slope. Example:- A young guy likes to keep a collection of high end sports cars. He plans to buy 5 Bentley Azures and 2 Convertible Corvettes (notice the price difference between the two). In such a situation, it is very obvious for the person not to compromise on Corvettes for an extra Bentley. Note:- This phenomena can also be explained via Indifference Curves
What is P1 Material?
P1 Material is the name given to Carbon Manganese Steel in the engineering industry
What is the formula of unitary elastic demand?
ed=(q1-q2)/q1/(p1-p2)/p1
