Wiki User
β 14y agoFor a positive integer value n, "to the power of" n means the number multiplied by itself n times. "To the power of n" is also defined for negative, rational, irrational and complex n, but all that is not required now.
So 5 to the power of 9 is 5*5*5*5*5*5*5*5*5 [that is, 9 lots of 5]. This is normally written as 59
So 59 = 5*5*5*5*5*5*5*5*5 = 25*5*5*5*5*5*5*5 = 125*5*5*5*5*5*5 = 625*5*5*5*5*5 = 3125*5*5*5*5 = 15625*5*5*5 = 78125*5*5 = 390625*5 and that is 1953125.
Wiki User
β 14y agoPower is the rate of doing work
P is power. Work is W. Time is t. Power is work divided by time, or, the rate at which work is done.
Did you mean find n where (2^5)^n = 64? (Sorry - the superscript symbol won't work!) I think that would need logarithms to calculate, because 2^5 = 32. Or did you mean find the power of 2 that = 64?
If you mean the symbol of a triangle, in math and science a triangle stands for change in
06= 0x0x0x0x0x0= 0
Power is the rate of doing work
Not necessarily. The amount of work depends on both the power and the amount of time it is applied. Less power may mean that the work is done more slowly, but the overall work done can still be the same as with more power but for a shorter duration.
Power is work per time, joules per second. So Power would be the rate at which work can be performed.
it means take the antenna out of the power outlet, it won't work!
it will be a cube or a to the power of 3.
P is power. Work is W. Time is t. Power is work divided by time, or, the rate at which work is done.
Because there is no power for the pump.
you must know time to determine both work and power
In various areas of power plants I would suspect.
Work done is calculated using the formula: Work = Force x Distance. If you have the result in joules and the time taken, you can calculate the power using the formula: Power = Work / Time. So, you can determine the power required to do 200j of work in 20s.
yes you would have power no matter what
Yes, because power is a measure of how quickly work is done. In this case, the power for the 200 joules of work done in 20 seconds would be 10 watts, while the power for the 50 joules of work done would be 2.5 watts. Hence, 200 joules of work done involves more power than 50 joules of work done.