145 subtracted by 180 = -35
222
(77 - 32)/1.8 = 45/1.8 = 25
-70
The everage mass of three men is: (a + b) / 3 = 77, where a is mass of two first men combined and b is a mass of third man. The everage mass of two men is: a / 2 = 72.5, therefore a = 145, and (145 + b) / 3 = 77 145 + b = 231 b = 231 - 145 = 86 Answer: Mass of the third man is 86 kg.
The number to be subtracted is 11.The number to be subtracted is 11.The number to be subtracted is 11.The number to be subtracted is 11.
The subtrahend is subtracted from the minuend
45 subtracted from184 = -139
136 subtracted by 89 = 47
2011 subtracted by 1960 = 51
1530 subtracted to 180 = 1350
2.3 subtracted from 20 = -17.7