145 subtracted by 180 = -35
222
(77 - 32)/1.8 = 45/1.8 = 25
-70
The everage mass of three men is: (a + b) / 3 = 77, where a is mass of two first men combined and b is a mass of third man. The everage mass of two men is: a / 2 = 72.5, therefore a = 145, and (145 + b) / 3 = 77 145 + b = 231 b = 231 - 145 = 86 Answer: Mass of the third man is 86 kg.
The number to be subtracted is 11.The number to be subtracted is 11.The number to be subtracted is 11.The number to be subtracted is 11.
The subtrahend is subtracted from the minuend
36.32 subtracted by 25.75 = 10.57
65 subtracted by 2012 = -1947
2012 subtracted by 1967 = 45
103.50 subtracted by 15.12 = 88.38
54 subtracted by 49 = 5