1x225, 3x75, 5x45, 9x25, 15x15
You are asking 32x52? This is 9x25 which is 225
Assuming you mean 9mm, and not calibre, you have a number of options. There's the 9x19 Parabellum/Luger, the 9x17 (more commonly known as the .380 ACP in the US), the 9x18 Makarov, the 9x21, the 9x23 Steyr, 9x23 Winchester, 9x25 Mauser 'Export', 9x25 Dillon... quite a variety to choose from. Most likely, you'd be referring to a 9x19 firearm (also known as 9mm Luger or Parabellum).
9 quarters make 9x25 =225 cents. Every 5 is a nickel so you get 225/5= 45 nickels. Or, if you like, 5 nickels in a quarter, so 9 quarters make 9x5=45 nickels.
The .380 ACP is a type of 9mm... 9x17, and is sometime referred to as the 9mm Short or 9mm Kurz. It is NOT the same as the 9mm Luger/Parabellum (9x19), and it is NOT compatible with any other type of 9mm cartridge (such as the 9x19 Luger/Parabellum, 9x18 Makarov, 9x21, 9x23, 9x25, etc.).
You can only get a specific number for an expression if you assign numbers to the variables. As an expression, the existing expression cannot be simplified.
The .380 ACP is 9x17, the 9mm Makarov is 9x18 (it should be noted the projectile for this round is actually 9.3 millimetres in diametre, as well), the 9mm Parabellum/Luger is 9x19. 9x21 is a commercial round intended for countries in which military calibres are prohibited for civilians to possess, and there are a few different 9x23 cartridges - 9x23 Winchester, which is fairly popular as an alternative to .38 Super for competitive shooting, 9x23 Steyr was a military cartridge which fell out of favour, and no current production firearms are manufactured for this cartridge. 9x25 Dillon is a 10mm casing necked down to a 9mm projectile, the 9x25 Mauser was a military cartridge which saw only limited service, and, like the 9x23 Steyr, no modern firearms are currently manufactured for this cartridge. Some also like to refer to the .357 Sig - which is a .40 S&W casing necked down to accept a 9mm projectile - as the 9x22, but this is in no way official, and it's typically referred to as .357 Sig, even in metric system countries. It should be noted that in the US, most of the time when someone refers to a 9mm, they're talking about the 9mm Luger (9x19mm Parabellum)
There are several different types of 9mm cartridge. When Snoop Dogg or some other rapper talks about his "nine", they're referring to a weapon firing the 9x19 cartridge, also known as the 9mm Parabellum or 9mm Luger. Other 9mm cartridges in common use include the 9x17, which is also known as the .380 ACP, and the 9x17 Makarov cartridge, which is popular with military surplus collectors. There have been several other 9mm cartridges made, both past and present, to include the 9x23, 9x25, 9x39, etc.
The .380 ACP is a 9mm cartridge - 9x17mm. That is the ONLY cartridge which can be fired from a .380 pistol, and the 9x18mm Makarov, 9x19mm Parabellum/Luger, 9x21, 9x23, 9x25, etc. cartridges are NOT compatible. The Makarov cartridge actually uses a 9.3mm projectile, which is too large for the .380, and the 9x19 cartridge uses too long a case, meaning you won't get proper headspacing in the chamber, and it's designed for a locked breech pistol, generating too much pressure to be safely used in an unlocked breech pistol such as a .380. Do not attempt to use any ammunition other than what your firearm is intended to shoot.
Associative Property is when you can change the group of factors . The product stays the same..Like (5x2)X4=10x4=40 same like 5X(2x4)=5x8=40 commutative property of multiplication is when you can change the order of the factors and the product stays the same. Like 7x4=28 & 4x7=28. Zero property of multiplication is when one of the factors is zero the product is always zero 8 x 0=0 0x4=0 identity property of multiplication is when one of the factors is one the product is always the other factor. 6x1=6 1x9=9 18x0=0 is Zero property because according to the definition when one of the factors is zero the product is always zeroin 18 * there is a zero. 9X25=25X9 is commutative property of multiplication because according to the definition you can switch it up and it will still be the same thing just like every other multiplication problem except the zero property.