Remember in basic Algebra we learned that all variables can be substituted as 1's If needed. So lets do that:
-k - 4k = -1 - 4(1) = -5
So now we can rewrite this removing the 1's we put in:
-k - 4k = -5k
To find the value of ( k ) for which ( 4K + 6 = 26 ) and ( 6k - 2 = 28 ), we can solve each equation. For ( 4K + 6 = 26 ): [ 4K = 20 ] [ K = 5 ] For ( 6k - 2 = 28 ): [ 6k = 30 ] [ k = 5 ] Both equations yield ( k = 5 ). Thus, when ( k = 5 ), both expressions have the same length.
Well, isn't that just a happy little equation we have here! When you multiply 4k by k, you simply multiply the coefficients (4 and 1) to get 4, and then add the exponents of k, which gives you k^2. So, 4k x k equals 4k^2. Just remember, there are no mistakes in math, only happy accidents!
k=-2
-4k + 10 - k + 2 = 2k + 4k + 18Combine all the 'k' terms on the left side:-5k + 10 + 2 = 2k + 4k + 18Combine all the 'k' terms on the right side:-5k + 10 + 2 = 6k + 18Combine the numerical terms on the left side:-5k + 12 = 6k + 18Add 5k to each side:12 = 11k + 18Subtract 18 from each side:-6 = 11kDivide each side by 11:k = -6/11
4k = 28 Therefore, 28/4 = 7 k = 7
4k-7 = 7 4k = 14 k = 3.5 or k = 7/2
31 = 3-4k 31-3 = -4k 28 = -4k Divide both sides of the equation by -4 to find the value of k: k = -7
8-4k = 40 (4k-8) - 8 = 40-8 4k = 32 4k/4 = 32/4 k =8
4k-64 = -60
q=4k+4uImproved Answer:-If: Q = 4k+4uThen: k = (4u-Q)/-4
-4k-2=10 -4k=10+2 -4k=12 k=-3
There are infinitely many of them.Take any positive integer k and let 0
x =√k+√k+√k…… ectx² = k + xx² - x = kx² - x + (1/2)² = k + (1/2)² factorise x² - x + (1/2)²(x + 1/2)² = k + 1/4(x + 1/2)² = (4k + 1)/4x + 1/2 = ± √(4k + 1)/2x = 1/2 ± √(4k + 1)/2it obviously has to be positivex = 1/2 + √(4k + 1)/2x = (1 + √(4k + 1))/2
Well, isn't that just a happy little equation we have here! When you multiply 4k by k, you simply multiply the coefficients (4 and 1) to get 4, and then add the exponents of k, which gives you k^2. So, 4k x k equals 4k^2. Just remember, there are no mistakes in math, only happy accidents!
J = K+6 K + J = 4K Replace J in the second equation K + (K + 6) = 4K K + K + 6 = 4K 2K + 6 = 4K Subtract 2K from each side 6 = 2K divide both sides by 2 3 = K So, Keisha is 3 and therefore John is 9
k=-2
k = 2