0.91 already IS in decimal form.
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cos x=.091 x=(cos^-1).091 x=84.779
If 18 091 997 is a series of three separate numbers the roman numerals for them would be 18 = XVIII, 091 = XCI and 997 = CMXCVII.
487,643,214= 299,749,123 + 187,894,091
No, the sum of a repeating decimal and a terminating decimal is never a terminating decimal.
A terminating decimal is a decimal that ends. A repeating decimal is a decimal that goes on and on.