38 with 13 remaining 621 - 13 = 608 = 16 x 38
To solve, 38 x x% = 9 x = 9/38 x 100 x = 24 9 is 24% of 38
x2 + 13x + 4 = (x + 6½ + √38¼)(x + 6½ - √38¼). To find this, we need to find p and q, where p + q = 13, pq = 4. 4 = 42¼ - 38¼ = (6½ + √38¼)(6½ - √38¼); thus, p = (6½ + √38¼), q = (6½ - √38¼).
38 x 18 = 684
573
38 with 13 remaining 621 - 13 = 608 = 16 x 38
That first number was probably 39, but as written... 2 x 19 = 38 2 x 2 x 13 = 52 13 x 13 = 169 2 x 2 x 13 x 13 x 19 = 12844, the LCM If it was 39, the LCM would have been 2028.
The answer would be 6,561. 38 = 6,561
Yes. Proof: 38*13% = 38*(13/100) = (38*13)/100 = 13*(38/100) = 13*38%
No. 38x25x4= 3800; 13x9= 117
The first five multiples of 38 is different from the first five multiples of 20! Who idoit would say they are the same?! Anyway these are the multiples... 38, 76, 114, 152, 190, 228. WELCOME :)
1 x 38 = 38 2 x 38 = 76 3 x 38 = 114 4 x 38 = 152 5 x 38 = 190 6 x 38 = 228 7 x 38 = 266 8 x 38 = 304 9 x 38 = 342 10 x 38 = 380 11 x 38 = 418 12 x 38 = 456
39 - 1 = 38
To figure this out, start by subtracting 13 from 38. (The answer is 25.) After that, you simply solve the equation 38+24+25=X. (x=87)
Just 37. 35 = 5 x 7 36 = 2 x 2 x 3 x 3 38 = 2 x 19 39 = 3 x 13
Oh, dude, factor pairs of 49? Like, let me think... okay, so we've got 1 and 49, and also 7 and 7. That's it. Easy peasy lemon squeezy.
To solve, 38 x x% = 9 x = 9/38 x 100 x = 24 9 is 24% of 38