Solve be substitution... m+n=1000 0.05m+0.06n=57 Take one of the equation and find "m" m=1000-n substitute into the other equation 0.05(1000-n)+0.06n=57 50-0.05n+0.06n=57 50-0.01n=57 -0.01n=-7 n=700 Now you have found "n" now find "m" m=1000-n m=1000-700 m=300 m=300 and n=700
Since one km = 1000 m and one cm = 0.01 meter, 150 cm = 150(0.01 m)/[1000 (m/km)], or (150 X 10-2/1000) km = 1.50 X 10-3 km.
The roman numeral "M" with a bar on top of it - denotes that the "M" or 1000 needs to be multiplied by 1000. So the M with a bar on top means 1000 x 1000 or 1,000,000.
150 = CL 1000 = M If you're asking someone here to write out all the numbers in between, then the answer is probably no.
The Roman numeral for 1000 is M and 1000000 can be writen as (M). The enclosing brackets denote that the numeral within should be multiplied by 1000.
It is 150/1000.
m *n (m multiplied by n) would be mn.
150 m/s
1,000 multiplied by 1,000 is 1,000,000.
1 cm multiplied by 1000 equals 1000 cm or 1 meter.
Solve be substitution... m+n=1000 0.05m+0.06n=57 Take one of the equation and find "m" m=1000-n substitute into the other equation 0.05(1000-n)+0.06n=57 50-0.05n+0.06n=57 50-0.01n=57 -0.01n=-7 n=700 Now you have found "n" now find "m" m=1000-n m=1000-700 m=300 m=300 and n=700
Since one km = 1000 m and one cm = 0.01 meter, 150 cm = 150(0.01 m)/[1000 (m/km)], or (150 X 10-2/1000) km = 1.50 X 10-3 km.
The roman numeral "M" with a bar on top of it - denotes that the "M" or 1000 needs to be multiplied by 1000. So the M with a bar on top means 1000 x 1000 or 1,000,000.
150 = CL 1000 = M If you're asking someone here to write out all the numbers in between, then the answer is probably no.
The Roman numeral for 1000 is M and 1000000 can be writen as (M). The enclosing brackets denote that the numeral within should be multiplied by 1000.
For a positive number, n, x raised to the power n is 1 multiplied by x n times. It is often wrongly described as x multiplied by itself n times.Thus, x^3 = x*x*x [ or 1*x*x*x] but notx multiplied by x multiplied by x multiplied by x which would be x^4.For negative integers, m, x^m = (1/x)^m = 1/(x^m)x^0 = 1 for all non-zero x.For fractional powers,x^(m/n) = the nth root of x^m or, equivalently, (nth root of x)^m.
F=ma a=F/M a=? F=75 N m=150 kg 75 N/150 Kg= .5 m/s^2 (1 N= 1kg x m/s^2) The acceleration of the boat is .5 m/s^2