1 million = 1,000,000 = 1000² Which means we want: (1000 + 1)² - (1000 - 1)² , that is 1001² - 999² However, before we work that out, lets look at what we have. let a = 1000, b = 1, then: (1000 + 1)² - (1000 - 1)² = (a + b)² - (a - b)² Now (a + b)² = a² +2ab + b² and (a - b)² = a² - 2ab - b² → (a + b)² - (a - b)² = a² +2ab + b² - (a² - 2ab - b²) = 4ab As a = 1000, b = 1, this means (1000 + 1)² - (1000 -1)² = 4 × 1000 × 1 = 4000.
1000
-984
0.1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111000010101010101111111111111111111111111111100000000000000000000000000000011111111111111111111111111111111111111110000000000000000000000000000000000000000000000000000000011111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111
Let x = abc be a 3-digit number. The expanded for of x is 100*a + 10*b + c.And let y = de = 10*d + e be a 2-digit number. Then x*y = 1000*a*d + 100*a*e + 100*b*d + 10*b*e + 10*c*d + c*e = 1000*a*d + 100*(a*e + b*d) + 10*(b*e + c*d) + c*e.
1 million = 1,000,000 = 1000² Which means we want: (1000 + 1)² - (1000 - 1)² , that is 1001² - 999² However, before we work that out, lets look at what we have. let a = 1000, b = 1, then: (1000 + 1)² - (1000 - 1)² = (a + b)² - (a - b)² Now (a + b)² = a² +2ab + b² and (a - b)² = a² - 2ab - b² → (a + b)² - (a - b)² = a² +2ab + b² - (a² - 2ab - b²) = 4ab As a = 1000, b = 1, this means (1000 + 1)² - (1000 -1)² = 4 × 1000 × 1 = 4000.
1000
All I can think of is 1000 billionths in a millionth
87.5% or B+
Phoenicians
play games
-984
There are infinitely many possible triplets.Suppose A is any positive real number that is less than 10 = cuberoot(1000).Let B be any positive real number between A and sqrt(1000/A).And let C = 1000/(A*B).This construction ensures that in each triplet (A, B, C), A < B < C so that each triplet is different and the same set is not being counted multiple times.Then, A*B*C = A*B*1000/(A*B) = 1000There are infintely many real numbers smaller than 10, there are therefore infinitely many choices for A.Then there are infinitely many real numbers between A and sqrt(1000/A), so there are infinitely many choices for B.Consequently, there are infinitely many possible solutions.
C equals the square root of 1000 or 31.622776601683793319988935444327...
100-1000 or so depending on specifics
Suppose there are b boys in the school. Then there are 2*b girls. So there are 2b + b = 3b girls and boys 3b = 1500 so b = 500 and then 2b = 1000 So there are 500 boys and 1000 girls.
500 mcg.