£2.70
10+10+5+2=27
do you mean a 50p coin or a £50 note. ---------------------------------- 3x9p = 27p 50p-27p = 23p £50 = 5000p 5000p-27p = 4973p = £49.73p
If: 837 = 27p Then: p = 31
If the ratio of the amount of money in David's pocket to that in Indira's pocket is 10:9, we can express this relationship mathematically. Indira has 27p, which corresponds to the 9 in the ratio. To find the amount David has, we can set up a proportion: ( \frac{D}{27} = \frac{10}{9} ). Solving for ( D ), we find that David has ( D = 27 \times \frac{10}{9} = 30p ). Thus, David has 30p.
1/3 of 27 p = 27 p/3 = 9 p
10+10+5+2=27
9p
27p = 2.70 /27 /27 ======== p = .1
do you mean a 50p coin or a £50 note. ---------------------------------- 3x9p = 27p 50p-27p = 23p £50 = 5000p 5000p-27p = 4973p = £49.73p
9p
27p per gal
331/3 % = 100/3 % = 100/3 ÷ 100 = 1/3 ⇒ 331/3 % of 27p = 1/3 x 27p = 9p
If: 837 = 27p Then: p = 31
If the ratio of the amount of money in David's pocket to that in Indira's pocket is 10:9, we can express this relationship mathematically. Indira has 27p, which corresponds to the 9 in the ratio. To find the amount David has, we can set up a proportion: ( \frac{D}{27} = \frac{10}{9} ). Solving for ( D ), we find that David has ( D = 27 \times \frac{10}{9} = 30p ). Thus, David has 30p.
27p
20p, 2p, 2p, 2p, 1p.
1/3 of 27 p = 27 p/3 = 9 p