-10 - 15 = -25
-25 - 10 = -35
-10
The resistors are 5, 10, and 15 ohms.The current through the 5-ohm resistor is E/R = 15/5 = 3 Amp.The current through the 10-ohm resistor is E/R = 15/10 = 1.5 Amp.The current through the 15-ohm resistor is E/R = 15/15 = 1 Amp.Their total effective resistance in parallel is the reciprocal of [ (1/5) + (1/10) + (1/15) ] =the reciprocal of [ (6/30) + (3/30) + (2/30) ] = the reciprocal of [ (11/30) ] = 30/11 ohms .The total current drawn from the battery is E/R = (15)/(30/11) = (15 x 11/30) = 11/2 = 5.5 Amp.Note:The 5-ohm resistor is dissipating 45 watts.The 10-ohm resistor is dissipating 22.5 watts.The 15-ohm resistor is dissipating 15 watts.The poor battery is delivering 82.5 watts.None of this is going to last very long at all.Most likely, the battery has already expired,and/or the 5-ohm resistor has already exploded,while we've been here playing with our calculators.
7/10 minus 9/15 is 1/10
-10 - 15 = -25
-25 - 10 = -35
-15-(-10)= -15+10= -5
Rt = 10
-5 - 10 = -15
-10
15 - 25 = -10
The current would be about 20 volts.
The resistors are 5, 10, and 15 ohms.The current through the 5-ohm resistor is E/R = 15/5 = 3 Amp.The current through the 10-ohm resistor is E/R = 15/10 = 1.5 Amp.The current through the 15-ohm resistor is E/R = 15/15 = 1 Amp.Their total effective resistance in parallel is the reciprocal of [ (1/5) + (1/10) + (1/15) ] =the reciprocal of [ (6/30) + (3/30) + (2/30) ] = the reciprocal of [ (11/30) ] = 30/11 ohms .The total current drawn from the battery is E/R = (15)/(30/11) = (15 x 11/30) = 11/2 = 5.5 Amp.Note:The 5-ohm resistor is dissipating 45 watts.The 10-ohm resistor is dissipating 22.5 watts.The 15-ohm resistor is dissipating 15 watts.The poor battery is delivering 82.5 watts.None of this is going to last very long at all.Most likely, the battery has already expired,and/or the 5-ohm resistor has already exploded,while we've been here playing with our calculators.
25 minus 15 is 10.
7/10 minus 9/15 is 1/10
9/10 minus 9/15 is 3/10