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1111111111
o.1111111111 recurring
1,111,111,111
No, 1023 it is not one of the multiples of the base 2 (binary) system. 1024 is. 1024 = 210. Of course 1023 can be represented in base 2 however as 1111111111.
the options i can see are: 1111111111 111111112 11111122 1111222 112222 22222 there are 6 combinations but i will need to reformulate to work out how many permutations of these 6 combinations there are
open 5555555555/777777777777
1111111111 x 1111111111 = 1234567900987654321
Oh honey, when you multiply 1111111111 by 1111111111, you get 1234567900987654321. Yep, that's right, just a fun little palindrome to make your day a bit more interesting. Math can be sassy too, you know!
123456790087654321
1111111111
1111111111
1111111111
1.234567900987654e+18
Yes because it can be expressed as a fraction
o.1111111111 recurring
1111111111
The repeating decimal .1111111111 can be represented as the fraction 1/9. This is because the decimal 0.1 can be expressed as 1/10, and when we have a repeating decimal like .1111111111, it is equivalent to 1/10 + 1/100 + 1/1000 + ... which simplifies to 1/9 using the formula for the sum of an infinite geometric series.