11 times 5 24 times = 1,320
5x - 11 = 24 5x = 35 x = 7
5/6 -3/8 = 6 times 8 = 48 6 times 3 = 18 5 times 8= 40 = 40/48 - 18/48 =40-18 = 22 (22/48) 22 divided 2= 11 48 divided 2= 24 =11/24
To find the number of combinations of 5 students that can be chosen from 24 students, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). In this case, ( n = 24 ) and ( k = 5 ), so the calculation is ( C(24, 5) = \frac{24!}{5!(24-5)!} = \frac{24!}{5! \cdot 19!} = \frac{24 \times 23 \times 22 \times 21 \times 20}{5 \times 4 \times 3 \times 2 \times 1} = 42504 ). Therefore, the teacher can choose from 42,504 different combinations of 5 students.
264
55 and its multiples. 1, 5, and 55 are all in both the 5 times and 11 times tables.
24*11 = 264
5x - 11 = 24 5x = 35 x = 7
120
5 * 1.1 = 5.5
24*5=120
5 x 5 x 11 x 11 is the prime factorization of 3025
5 times 24 = 120.
5/6 -3/8 = 6 times 8 = 48 6 times 3 = 18 5 times 8= 40 = 40/48 - 18/48 =40-18 = 22 (22/48) 22 divided 2= 11 48 divided 2= 24 =11/24
80 x 24 x 5 = 9,600
11 * 5 * 4 = 220 ■
The Least Common Multiple (LCM) of 11 and 24 is 264. This is found from 11 times 24.
13 and 11.