No. For example, a 12x1 and a 4x3 quadrilateral both have an area of 12, but they are not congruent.
12x1=12 12x2=24 12x3=36 12x4=48 12x5=60 12x6=72
12x1=12 12x2-24 12x3=36 12x4=48 12x5=60 12x6=72 12x7=84 12x8=96 12x9=108 12x10-120 12x11=132
The LCM is 36. In this case it is easy to look at the multiples of 12. The first one is 12x1 and that does not work. 24 is 12x2 and 9 does not go into that. But 36 is 12x3 and both 6 and 9 divide it evenly. So that tells us the LCM is 36.
364 1x12=12 2x11=22 3x10=30 4x9=36 5x8=40 6x7=42 7x6=42 8x5=40 9x4=36 10x3=30 11x2=22 12x1=12 Added up equals 364
24x1 12x1
12x1 6x2 4x3 Thats it
12x1
34.12
60
since 12 is a multiple of 3 and itself (12x1), 12 is the LCM of 3 and 12
No. For example, a 12x1 and a 4x3 quadrilateral both have an area of 12, but they are not congruent.
5x114.3. Center Bore: 67.1. Hardware: 12x1. 50 Lug Offset: 45-55mm
12x1=12 12x2=24 12x3=36 12x4=48 12x5=60 12x6=72
There is 8 of them 12x1=12 12x2=24 12x3=36 12x4=48 12x5=60 12x6=72 12x7=84 12x8=96
12 3x4=12 4x3=12 12x1=12
it would be 12x1 12x2 12x3 12x4 12x5 12x6 12x7 12x8 12x9 12x10 and so on like 12 24 36 48 60 72 84 96 108