x = 3/5 and y = 1/5
20x+12y = 2012 12y = -20x+2012 y = -5/3x+503/3 Therefore the perpendicular slope is the positive reciprocal -5/3 which is 3/5
5*3y+1+12y-1 = 15y+1+12y-1 = 27y.
53 x 5 = 265
It equals 24.
x = 3/5 and y = 1/5
20x+12y = 2012 12y = -20x+2012 y = -5/3x+503/3 Therefore the perpendicular slope is the positive reciprocal -5/3 which is 3/5
5*3y+1+12y-1 = 15y+1+12y-1 = 27y.
x = 8
53
24
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7
-6y + 5 = -67y=12-6y = -72-y = -12y = 12
In the given expression you replace x by 2 and y by 1. Thus 5xy + 7x2 - 12y = 5*x*y + 7*x2 - 12*y = 5*2*1 + 7*22 - 12*1 = 10 + 28 - 12 = 26
The sum of 7/15 and 5/12 equals 53/60
53 x 5 = 265