It is 13 and as a product of its prime factors: 2*5*13 = 130
If there were two prime factors of 130, then they would have to be the only possible factors of 130.If either of them could be broken down to smaller factors, it wouldn't be a prime number.In addition to '1' and '130' ... 2, 5, 10, 13, 26, and 65 are also factors of 130. So there can't be two prime factors.
The product of the prime factors of any number is equal to the number itself. Therefore, the product of the prime factors of 350 is 350.
The product of the prime factors of a number is the number itself.
As a product of its prime factors: 225*5 = 100
It is 13 and as a product of its prime factors: 2*5*13 = 130
As a product of its prime factors: 2*5*13 = 130
No
If there were two prime factors of 130, then they would have to be the only possible factors of 130.If either of them could be broken down to smaller factors, it wouldn't be a prime number.In addition to '1' and '130' ... 2, 5, 10, 13, 26, and 65 are also factors of 130. So there can't be two prime factors.
Need to solve for more factors: (use link) http://www.classbrain.com/artteach/publish/article_48.shtml?num=81&worksp= Answer: The factors of 130 are: 1 2 5 10 13 26 65 130 The prime factors are: 2 x 5 x 13
The prime factors of 130 are: 2 5 13.
The product of factors is called the product.The product of prime factors is called the prime factorization.
Multiply prime numbers or prime factors to find their product.
The product of the prime factors of any number is equal to the number itself. Therefore, the product of the prime factors of 350 is 350.
130 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 8 factors of 130 are 1, 2, 5, 10, 13, 26, 65, and 130.The factor pairs of 130 are 1 x 130, 2 x 65, 5 x 26, and 10 x 13.The proper factors of 130 are 1, 2, 5, 10, 13, 26, and 65 or,if the definition you are using excludes 1, they are 2, 5, 10, 13, 26, and 65.The prime factors of 130 are 2, 5, and 13.The distinct prime factors of 130 are also 2, 5, and 13.The prime factorization of 130 is 2 x 5 x 13.
The product of the prime factors of a number is the number itself.
As a product of its prime factors: 225*5 = 100